How you find factorial of 100 in c?

Answer 1

hi friend

hope u got the ans:

int main()

{

int count=1,n,fact=1;

printf("Enter the value which u need for factorial");

scanf("%d",&n);

while(count<=n)

{

fact=fact*count;

count++;

}

printf("%d",fact);

getch();

}

The answer will get out of the scope of "int" when reaching 10! or 12!, so the upper answer is not accurate but in case of syntax it is good.

Below I have used array rather than simple int or long to store the multiplied results.

#include

#include

#define MAX 10000

int len = 0;

int fact[MAX];

void factorial(int);

void multiply(int);

void main()

{

int n,i;

clrscr();

printf("\nEnter any integer number : \n");

scanf("%d",&n);

fact[0]=1;

factorial(n);

printf("\nFactorial of %d is :\n",n);

for(i=len;i>=0;i--){

printf("%d",fact[i]);

}

getch();

}

void factorial(int n)

{

int i;

for(i=2;i<=n;i++){

multiply(i);

}

}

void multiply(int n)

{

long i,r=0;

int arr[MAX];

for(i=0;i<=len;i++)

{

arr[i]=fact[i];

}

for(i=0;i<=len;i++)

{

fact[i] = (arr[i]*n + r)%10;

r = (arr[i]*n + r)/10;

}

if(r!=0)

while(r!=0)

{

fact[i]=r%10;

r= r/10;

i++;

}

len = i-1;

}

Answer 2

The built-in types do not allow you handle factorials greater than 20! A long double will extend the range through approximation, but to calculate 100! you will need to design a user-defined type that can store a variable-length integer and perform the multiplication manually.

Answer 3

long n, factorial;

for (n=1, factorial=1; n <= 10; n++) {

factorial *= n;

printf ("%d %d\n", n, factorial);

}