#include<stdio.h>
#include<conio.h>
main()
{
int n,s,r,t;
clrscr();
printf("enter n");
scanf("%d",&n);
s=0;t=0;
while(n!=0)
{
r=n%10;
{
if(r%2!=0)
t=t+r;
if(r%2==0)
s=s+r;
}
n=n/10;
}
printf("sum of even position digits%d\n",s);
printf("sum of odd position digits%d\n",t);
getch();
}
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
public static void main(String[] args) { int val = 100; int val1 = 50; System.out.println("Number of digits in " + val + " is: " + new String(val + "").length()); System.out.println("Number of digits in " + val1 + " is: " + new String(val1 + "").length()); }
The tricky part is getting the individual digits. There are basically two ways to do this: 1) Convert the number to a string, and use string manipulation to get the individual digits. 2) Repeatedly divide the number by 10. The digit is the remainder (use the "%" operator). To actually get the highest digit, initially assume that the highest digit is zero (store this to a variable, called "maxDigit" or something similar). If you find a higher digit, replace maxDigit by that.
Check digits are determined (or derived) by a set algorithm using the digits of the account number.
The radix refers to the base of a number system: the total number of possible digits. The decimal number system that we all use is base ten, as it has ten distinct digits (0,1,2,3,4,5,6,7,8,9). Commonly used bases in computing include binary, octal, and hexadecimal, which have two, eight, and sixteen digits, respectively.
no thanks
To count the number of times a digit occurs in an integer, start by initializing an array of ten counts of digits, such as int digits[10];Then, in a loop while the number is non zero, increment the element in the digits array that corresponds to the units digit, and then divide the number by ten, such as digits[number%10]++ and number/=10;int digits[10];int i;int number = some number;for (i=0; i
#include <stdio.h> int main(int argc, char **argv) { if (argc<1) { printf("Usage: %s number\n",argv[0]); return -1; } int digits=1, i=atoi(argv[1]); while (i/=10) ++digits; printf("%d\n",digits); }
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
The number 1,234,567,890,123 has thirteen digits.
A Merchant Number is usually between 6 and 15 digits long. Examples: Natwest Streamline Merchant Number = 8 digits HSBC Merchant Number = 8 digits Lloyds TSB Cardnet Merchant Number = 15 digits Bank of Scotland Merchant Number = 15 digits Barclays Merchant Services Merchant Number = 7 digits American Express Merchant Number = 10 digits Diners Club Merchant Number = 10 digits JCB (Japan Credit Bureau) Merchant Number = 13 digits Elavon Merchant Number = 10 digits AIB (Allied Irish Bank) Merchant Number = 11 digits Ulster Bank (For Ireland Vendors only) Merchant Number = 8 digits Chase Payment Tech Merchant Number = 6 digits
The least whole number with 6 digits is greater because it has more digits than 5 digits.
The largest ten digit number with no repeated digits is '9876543210'.
no, it matters with the number not digits
which is greater, whole number with 5 digits or the whole number with 6 digits?
Digits is how many numbers you have in a number. If you have the number 4 it has one digit if you have the number 20 it has two digits and if you have the number 558 it has three digits. So basically in the number 1085 it has 4 digits because there is 4 numbers in it, the numbers are 1,0,8 and 5. Hoped you understand.