Here You go...........
# include<stdio.h>
# include<conio.h>
void main()
{
int no,sum=0,rem=0;
clrscr();
printf("\nEnter a Number: ");
scanf("%d",&no);
while(no>0)
{
rem=no%10;
sum=sum+rem;
no=no/10;
}
printf("\nSum of digits of a number: %d",sum);
getch();
}
no thanks
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
Add the digits together. The sum of the digits of 23 is 5.
Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.
Add the digits together. The sum of the digits of 23 is 5.
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
#include <stdio.h> void main() { int digi,num,i,sum=0; printf("Enter the number of digits:"); scanf("%d",&num); while(i>0); { for(i=0;i<10000;i++) { digi=num; i=digi%10; sum=sum+i; num=digi/10; } printf("The sum of digits entered is %d",sum); } }
45
192
26
the sum of my digits is 6? answer=60
34.