Here You go...........
# include<stdio.h>
# include<conio.h>
void main()
{
int no,sum=0,rem=0;
clrscr();
printf("\nEnter a Number: ");
scanf("%d",&no);
while(no>0)
{
rem=no%10;
sum=sum+rem;
no=no/10;
}
printf("\nSum of digits of a number: %d",sum);
getch();
}
no thanks
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
Add the digits together. The sum of the digits of 23 is 5.
Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.
Add the digits together. The sum of the digits of 23 is 5.
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
In QBASIC, you can write a simple program to input the number 64751315 and sum its digits as follows: DIM sum AS INTEGER sum = 0 INPUT "Enter a number: "; number FOR i = 1 TO LEN(number) sum = sum + VAL(MID$(number, i, 1)) NEXT PRINT "The sum of the digits is "; sum This program prompts the user to input a number, iterates through each digit, converts it to an integer, and adds it to the total sum, which is then printed out.
#include <stdio.h> void main() { int digi,num,i,sum=0; printf("Enter the number of digits:"); scanf("%d",&num); while(i>0); { for(i=0;i<10000;i++) { digi=num; i=digi%10; sum=sum+i; num=digi/10; } printf("The sum of digits entered is %d",sum); } }
An Armstrong number (or narcissistic number) for a given number of digits is a number that is equal to the sum of its own digits raised to the power of the number of digits. Here’s a simple Visual Basic 10 program that checks for Armstrong numbers: Module ArmstrongNumber Sub Main() Dim num As Integer Dim sum As Integer = 0 Console.Write("Enter a number: ") num = Convert.ToInt32(Console.ReadLine()) Dim temp As Integer = num Dim digits As Integer = num.ToString().Length While temp > 0 Dim digit As Integer = temp Mod 10 sum += Math.Pow(digit, digits) temp \= 10 End While If sum = num Then Console.WriteLine(num & " is an Armstrong number.") Else Console.WriteLine(num & " is not an Armstrong number.") End If End Sub End Module This program takes a number as input, calculates the sum of its digits raised to the power of the number of digits, and checks if the sum equals the original number.
45
192
26