C programming of bisection method with output?

Answer 1

try this out...

#include

#include

float valcal(float);

int main(){

float a,b,f,x,f1,f2,f3,i;

a=2;

b=3;

int flag=0;

f1=valcal(a);

f2=valcal(b);

//printf("\n\n%f %f",f1,f2);

for(i=0;i<7;i++){

if(f1*f2<0){

x=((a+b)/2)

;flag=1;

//printf("\n\nval of x : %f",x);

}

f3=valcal(x);

//printf("\n\nf3: %f",f3);

//(f3<0)?(f1=f3):(f2=f3);

if(f3<0){

f1=f3;

a=x;

}

else{

f2=f3;

b=x;

}

}

if(flag==1)

printf("\n\nTHE SOL IS : %f",x);

else

printf("\nNO SOLUTION\n");

printf("\n\n");

system("pause");

}

float valcal(float x){

float f;

f=((x*x*x)-(4*x)-9);

return f;

}

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