In the equation N2+3H2=2NH3, the amount of ammonia produced from 50g of N would be 16.667g.
viscosity is increasing
The balanced equation for the production of ammonia is the following: N2 + 3H2 ---> 2NH3
The chemical formula for ammonia is NH3.
Nitrogen Gas + Hydrogen Gas --> Ammonia Gas Or 2H3 + N2 --> 2NH3 This is a balanced equation. The general formula for ammonia is NH3
8,038 moles of ammonia were produced.
viscosity is increasing
The balanced equation for the production of ammonia is the following: N2 + 3H2 ---> 2NH3
The word equation for ammonia is 3 H2 + N2 → 2 NH3 (this is a balance equation) The formula (atom) is NH3 for ammonia
The chemical formula for ammonia is NH3.
To determine the mass of ammonia consumed, we need the balanced equation for the reaction. Without that information, we cannot accurately calculate the amount of ammonia consumed by the reaction of g of oxygen gas.
Ammonia-NH3 2N+3H2=2NH3 2moles of Nitrogen produced 2moles of Ammonia (2*14)g of Nitrogen produced (2*17)g of Ammonia 28g of Nitrogen produced 34g of Ammonia 34g of Ammonia is produced by 28g of Nitrogen 0.034kg of Ammonia is produced by 0.028kg of Nitrogen 91.3kg of Ammonia will be produced by 0.028*91.3/0.034 91.3kg of Ammonia will be produced by 75.19kg of Nitrogen FOR HYDROGEN: 3moles of H2 produces 2moles of NH3 (2*3)g H2 produces 2*17g NH3 6g hydrogen produces 34g ammonia 0.006kg hydrogen produces o.o34kg ammonia 91.3kg ammonia will be produced by 91.3*0.006/.034=16.11kg of Hydogen Therefore, 75.19kg of Nitrogen and 16.11kg of Hydrogen will produce 91.3kg of Ammonia
Nitrogen Gas + Hydrogen Gas --> Ammonia Gas Or 2H3 + N2 --> 2NH3 This is a balanced equation. The general formula for ammonia is NH3
8,038 moles of ammonia were produced.
NH3
ammonia + oxygen --> nitrogen monoxide + water
ammonia gas -NH3
Nh4OH