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Calculate the amount of ammonia produced from 50g of N in the equation N2+3H2=2NH3?
In the equation N2+3H2=2NH3, the amount of ammonia produced from 50g of N would be 16.667g.
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If 250.3 L of hydrogen gas (d 0.0899gL ) reacts with an excess of nitrogen gas what mass of ammonia would be produced?
To determine the mass of ammonia produced, you first need to calculate the moles of hydrogen gas present. Then, you can use the stoichiometry of the balanced chemical equation for the reaction between hydrogen and nitrogen to find the moles of ammonia produced. Finally, using the molar mass of ammonia, you can convert moles to grams to find the mass of ammonia produced.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?
The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.
How many moles of water vapor can be produced from 2 moles of ammonia?
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
If 250.3 L of hydrogen gas (d 0.0899gL ) reacts with an excess of nitrogen gas what mass of ammonia would be produced?
To determine the mass of ammonia produced, you first need to calculate the moles of hydrogen gas present. Then, you can use the stoichiometry of the balanced chemical equation for the reaction between hydrogen and nitrogen to find the moles of ammonia produced. Finally, using the molar mass of ammonia, you can convert moles to grams to find the mass of ammonia produced.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?
The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
What is the mole ratio of nitrogen to ammonia in the equation 1N2 3H2 equals NH3?
The balanced equation for the reaction is N2 + 3H2 --> 2NH3 Thus, the mole ratio of nitrogen to ammonia in the balanced equation is 1:2.
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
How many moles of water vapor can be produced from 2 moles of ammonia?
The balanced chemical equation for the reaction between ammonia (NH3) and water (H2O) is: 4NH3 + 5O2 → 4NO + 6H2O. This means that for every 4 moles of ammonia, 6 moles of water are produced. Therefore, if 2 moles of ammonia are used, 3 moles of water vapor can be produced.
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
If you reacted 88.9 grams of ammonia with excess oxygen?
The reaction between ammonia and oxygen will form nitrogen dioxide and water as products. Balancing the equation reveals that 4 moles of NH3 react with 7 moles of O2. To determine the amount of N2O4 produced, you will need to calculate the limiting reactant first.
When g of nitrogen and 6g of hydrogen react 34g of ammonia are product?
The reaction between nitrogen and hydrogen to produce ammonia is a synthesis reaction. The balanced chemical equation is N2 + 3H2 → 2NH3. By using the given amounts of nitrogen and hydrogen, we can calculate that 34g of ammonia should be produced, indicating that the reaction has gone to completion based on the law of conservation of mass.
What is the word equation for making ammonia?
Nitrogen Gas + Hydrogen Gas --> Ammonia Gas Or 2H3 + N2 --> 2NH3 This is a balanced equation. The general formula for ammonia is NH3
What's the word equation for nitrogen hydrogen - ammonia?
The word equation for ammonia is 3 H2 + N2 → 2 NH3 (this is a balance equation) The formula (atom) is NH3 for ammonia
