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How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
When 500g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1789g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
How many grams of ammonia NH3 will be prepared when 6.00g of hydrogen H2 has reacted?
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
How many grams are there in 200 g of ammonia?
There are 200 grams of ammonia in 200 grams of ammonia.
When the amount of oxygen is limited carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
How many grams of oxygen are needed to react with 23.9 grams of ammonia?
The balanced equation for the reaction between ammonia (NH3) and oxygen (O2) is 4NH3 + 5O2 → 4NO + 6H2O. To find the grams of oxygen needed to react with 23.9 grams of ammonia, you need to calculate the molar ratio between ammonia and oxygen using the balanced equation. Once you find the molar ratio, you can calculate the grams of oxygen required.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
When 500g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1789g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
How many grams of ammonia NH3 will be prepared when 6.00g of hydrogen H2 has reacted?
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
How many grams of NH3 can be produced from 2.63 mol of N2 and excess H2?
89,6 g ammonia are obtained.
How many grams are there in 200 g of ammonia?
There are 200 grams of ammonia in 200 grams of ammonia.
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
Balanced equation first. N2 + 3H2 >> 2NH3 (hydrogen is limiting and drives the reaction ) 3.41 grams H2 (1mol/2.016g )(2mol NH3/3mol H2 )(17.034g NH3/1mol NH3 ) = 19.2 grams of ammonia produced ( this is called the Born-Haber process )
If you burn 24.2 of hydrogen and produce 216 of water how much oxygen reacted?
To determine the amount of oxygen that reacted when burning hydrogen, we can use the balanced chemical equation for the combustion of hydrogen: 2 H₂ + O₂ → 2 H₂O. From the equation, 2 moles of hydrogen produce 2 moles of water, meaning 1 mole of hydrogen produces 1 mole of water. Given that 24.2 grams of hydrogen (approximately 12.1 moles) produce 216 grams of water (approximately 12 moles), we can see that 12 moles of water would require 6 moles of oxygen, which corresponds to about 192 grams of oxygen. Thus, approximately 192 grams of oxygen reacted.
How many grams of NH 3 can be produced from 3.91 mol of N 2 and excess H 2?
110 g ammonia are produced.
How much water wold form if 14.8 grams of hydrogen reacted with 34.8 grams of oxygen?
45 g water are obtained.
When the amount of oxygen is limited carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
