Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
When sodium sulfide and cadmium nitrate are mixed, a double displacement reaction occurs. The sodium from sodium sulfide switches places with the cadmium from cadmium nitrate to form sodium nitrate and cadmium sulfide. Cadmium sulfide is a yellow solid that precipitates out of the solution.
When you add sodium sulfide to tin chloride, a precipitation reaction occurs which forms tin sulfide, NaCl, and Na2SO4. Tin sulfide is a solid that precipitates out of solution.
The balanced chemical equation for the decomposition of solid sodium sulfide (Na2S) in aqueous solution is: 2Na2S(s) -> 2NaOH(aq) + H2S(g)
sodium and sulfide
The formula of the ionic compound composed of sodium and sulfide ions is Na2S. This is because the charges of sodium and sulfide ions are +1 and -2 respectively, so two sodium ions are needed to balance the charge of one sulfide ion.
The chemical name for Na2S is sodium sulfide. It is composed of two sodium (Na) ions and one sulfide (S) ion. Sodium sulfide is commonly used in industries such as paper production and water treatment.
There will be no reaction. It will remain a mixture.
The purpose of titrating sodium hydroxide with an acid solution is to determine the concentration of the acid solution. By carefully adding the acid solution to the sodium hydroxide until the reaction reaches equivalence, the amount of acid needed can be used to calculate its concentration.
Sodium chloride solution is neutral.
You can calculate the concentration of a phosphoric acid solution by determining the volume of sodium hydroxide needed to neutralize it in a titration. The molarity of the sodium hydroxide solution and the balanced chemical equation for the reaction will allow you to find the moles of phosphoric acid present, hence the concentration.
In sodium sulfide (Na2S), two sodium ions are needed for every sulfide ion to balance the charges. Sodium has a +1 charge, and sulfide has a -2 charge. By having two sodium ions (each with a +1 charge) for every sulfide ion (with a -2 charge), the overall compound achieves charge neutrality.
The formula of sodium sulfide, Na2S, indicates that each sodium sulfide molecule contains two sodium (Na) ions and one sulfide (S) ion. The ratio of sodium ions to sulfide ions in sodium sulfide is 2:1.