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Calculate the approximate volume of a 600 mol sample of gas at 15.0c and a pressure of 1.10atm?
Wiki User
∙ 12y ago
You really should do your own homework.
PV = nRT ==> V = nRT/P
T = 15 c = 288.15 K
P = 1.10 ATM (gauge) = 2.1 ATM (absolute) = 212.783 kPa
R = 8314.472 kPa cm^3/(gram mole deg K)
n = 600 gram moles
V = 600 gram moles x 8314.472 kPa cm^3/(mole K) x 288.15 K / 212.783 kPa 6.756 x 10^6 cm^3 6,759 liters
Wiki User
∙ 12y ago
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