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The mass of solid AgBr that is produced when 100.0 ml of 0.150 M AgNO3 is added to 20.0 ml of 1.00 M NaBr 2.82g.

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1w ago

To find the mass of AgBr formed, first calculate the moles of AgNO3 in 35.5 mL of 0.184 M solution. Then, use the mole ratio from the balanced chemical equation between AgNO3 and AgBr to find the moles of AgBr formed. Finally, multiply the moles of AgBr by its molar mass to get the mass. Note that since HBr is in excess, AgNO3 will be the limiting reagent.

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11y ago

1.23 grams

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Q: Calculate the mass of AgBr is formed when 35.5mL of 0.184 M AgNO3 is treated with an excess of aqueous hydrobromic acid HBr?
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