The white precipitate of silver chloride will dissolve when aqueous ammonia is added.
Should be a white precipitate. Indicative of the presence of either Na or Mg. Wrong again people. Silver Nitrate is used to test for the presence of chloride ions. Such as those in your salt a.k.a sodium chloride and yes adding silver nitrate to your salt solution will create a white precipitate.
The evidence that would lead you to believe that a residue was potassium chloride is it's white crystalline structure. When potassium chloride is mixed with water and the water evaporates, it leaves behind small potassium chloride crystals.
Naturally, Sodium is a metal (solid) and chlorine is a gas, so they only react at high temperatures or pressure. When they do react, they form crystals (sodium chloride).
Reagents and Indicators R-13-1Analytical Methods of the Member Companies of theCorn Refiners Association, Inc.Accepted 4-15-86MERCURIC NITRATE SOLUTIONPREPARATION0.02N Mercuric Nitrate Solution: For chloride determination. Dissolve 3.3 g ofreagent grade mercuric nitrate (Hg(NO3)2) in about 100 mL of purified watercontaining 0.25 mL of concentrated nitric acid (70% HNO3, sp g 1.42). Dilute to1 L with purified water, and mix.STANDARDIZATIONDry a quantity of analytical grade sodium chloride (NaCl) 30 minutes at 105°C;cool in desiccator. Dissolve 0.8241 g of dry sodium chloride in purified water,dilute to 1 L volume, and mix.Pipet 5.00 mL of the above sodium chloride solution, containing 2.5 mg chloride,into each of three 250 mL glass stoppered Erlenmeyer flasks. Add 85 mL ofpurified water, 10 mL of diphenylcarbazone indicator solution, 1 mL of 30%hydrogen peroxide solution, and 1.0 mL of 0.5N nitric acid solution (Note 1) toeach of the flasks. Stopper flasks and swirl contents. Prepare a reagent blank in a250 mL Erlenmeyer flask containing 90 mL of purified water, 10 mL ofdiphenylcarbazone indicator solution, 1 mL of 30% hydrogen peroxide solution,and 1.0 mL of 0.5N nitric acid solution; mix. Titrate the blank with mercuricnitrate solution to the purple indicator end point. Color development near the endpoint is slow, and as much as 30 seconds should be allowed between titrant dropsto facilitate full indicator color development (Note 2). Titrate the three standardsin the same manner to the same color end point. Observe and record the titers.Calculate average normality.CALCULATION(mL Hg(NO ) Titer - Blank)×35.452.5mgNormality =3 2Reagents and Indicators R-13-2MERCURIC NITRATE SOLUTION⎯ continuedNOTES AND PRECAUTIONS1. Treatment with hydrogen peroxide destroys interfering sulfites by oxidationto sulfates, and the nitric acid addition adjusts acidity to the proper level(pH about 2.5).2. Care should be exercised as the end point is approached, and it is expedientto observe the reaction mixture over a white surface. End point detection isfacilitated by running the blank first, and then titrating the standards tomatch the color of the blank.
Take some copper sulfate solid and add it to a beaker of water. Stir and you will see that the solid slowly disappears to form a blue solution. Copper sulfate has dissolved and is therefore soluble in water. Anhydrous copper sulfate is a white solid while hydrated copper sultate (CuSO4.5H2O) is blue.
When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.
If chloride is present silver chloride with get precipitated..
The solution would become a deep blue color as the ammonia forms coordinate covalent bonds to the copper II cations.
You would observe precipitation of magnesium hydroxide.
there is no change
The solution color of cupric oxide is blue to green.
The dihydrated salt is blue-green.
A red-brown precipitate of copper acetylide is formed.
You might see the smokey 'fume' of ammonium chloride solid particles formed by reaction of escaping ammonia and hydrogen chloride gas, at best seen when solutions are rather concentrated.NH3(g) + HCl(g) --> NH4Cl(s)
A white precipitate, lead (II) chloride, and aqueous sodium nitrate would form. The chemical equation is Pb(NO3)2(aq) + 2NaCl(aq) --> 2NaNO3(aq) + PbCl2(s). This type of reaction is called a double replacement or double displacement.
solution
The melting point of sodium chloride is 801 0C.