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Calculate the specific heat of a 55.6 g of material if its temperature decreases by 14.8 degrees Celsius when it loses 3080 J of heat What is its specific heat?
Wiki User
∙ 12y ago
q = m x C x ΔT
q = amount of heat energy gained or lost by substance = -3080J
m = mass of sample in grams = 55.6g
C = heat capacity (J/g•oC) = ?
ΔT = -14.8 oC
C = q/m•ΔT = -3080J/(55.6g)(-14.8 oC) = 3.74J/g•oC
Wiki User
∙ 11y ago
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