Power can be calculated in each individual phase and summed together. If the voltage is supplied L-N in RMS: P = V*I. Note this will give the same answer as calculating balanced three phase power from the equation P = V*I*sqrt(3)
Blondel's Theorem tells us that, to measure the total power of a three-phase load (balanced or unbalanced), we can use one less wattmeter than there are conductors supplying that load.So the two-wattmeter method will work for anythree-phase load, provided there are only threeconductors supplying that load, e.g. three-wire delta or three-wire star (wye).Bear in mind that wattmeter's read true power (expressed in watts) and ignores the reactive power of inductors and capacitors.
To calculate watts you need two of the three: Voltage (V), Current (A) and Resistance (ohm). Power (Watts) = (V^2) / R = (I^2)R = VI
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
Electric power is measured in watts. It does not matter if it is single phase or three phase. All things being equal, for the same load, the power measured in a single phase circuit or a three phase circuit, will be the same.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
You will need to determine the power per phase, and add them up to give the total power of the three-phase load. To do this, you will need to multiply the phase-voltage by the phase current by the power factor -for each phase.
Try 746 watts = 1 HP
317.025280 KILOWATTS = 317,025.28 WATTS
The most basic calculation is volts multiplied by amps of a circuit for a single phase load.
Just multiply. (Note, this assumes no phase difference.) <<>> The formula you are looking for is W = I x E. Watts = Amps x Volts.
Blondel's Theorem tells us that, to measure the total power of a three-phase load (balanced or unbalanced), we can use one less wattmeter than there are conductors supplying that load.So the two-wattmeter method will work for anythree-phase load, provided there are only threeconductors supplying that load, e.g. three-wire delta or three-wire star (wye).Bear in mind that wattmeter's read true power (expressed in watts) and ignores the reactive power of inductors and capacitors.
To convert amperage to watts, you need to know the voltage, power factor, and the number of phases that you are working with. For a residential refrigerator this is single phase, an industrial refrigerator could be three phase.
To calculate watts you need two of the three: Voltage (V), Current (A) and Resistance (ohm). Power (Watts) = (V^2) / R = (I^2)R = VI
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
21.739 a 21.739 a
Electric power is measured in watts. It does not matter if it is single phase or three phase. All things being equal, for the same load, the power measured in a single phase circuit or a three phase circuit, will be the same.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?