Power can be calculated in each individual phase and summed together. If the voltage is supplied L-N in RMS: P = V*I. Note this will give the same answer as calculating balanced three phase power from the equation P = V*I*sqrt(3)
Blondel's Theorem tells us that, to measure the total power of a three-phase load (balanced or unbalanced), we can use one less wattmeter than there are conductors supplying that load.So the two-wattmeter method will work for anythree-phase load, provided there are only threeconductors supplying that load, e.g. three-wire delta or three-wire star (wye).Bear in mind that wattmeter's read true power (expressed in watts) and ignores the reactive power of inductors and capacitors.
To calculate watts you need two of the three: Voltage (V), Current (A) and Resistance (ohm). Power (Watts) = (V^2) / R = (I^2)R = VI
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
Electric power is measured in watts. It does not matter if it is single phase or three phase. All things being equal, for the same load, the power measured in a single phase circuit or a three phase circuit, will be the same.
Question is incorrect. in a 240 Volt single phase circuit, how can you have A phase and B phase?
You will need to determine the power per phase, and add them up to give the total power of the three-phase load. To do this, you will need to multiply the phase-voltage by the phase current by the power factor -for each phase.
Try 746 watts = 1 HP
317.025280 KILOWATTS = 317,025.28 WATTS
To convert amperage to watts, you need to know the voltage, power factor, and the number of phases that you are working with. For a residential refrigerator this is single phase, an industrial refrigerator could be three phase.
To calculate the total power in watts used by a service panel with three-phase power, you would multiply the average current for each phase by the voltage and by the square root of 3 (√3 or approximately 1.73). This accounts for the fact that power in a three-phase system involves the line-to-line voltage and the square root of 3 relationship. So, the formula for total power (in watts) would be P = (Iavg x V x √3).
The most basic calculation is volts multiplied by amps of a circuit for a single phase load.
Blondel's Theorem tells us that, to measure the total power of a three-phase load (balanced or unbalanced), we can use one less wattmeter than there are conductors supplying that load.So the two-wattmeter method will work for anythree-phase load, provided there are only threeconductors supplying that load, e.g. three-wire delta or three-wire star (wye).Bear in mind that wattmeter's read true power (expressed in watts) and ignores the reactive power of inductors and capacitors.
To calculate watts you need two of the three: Voltage (V), Current (A) and Resistance (ohm). Power (Watts) = (V^2) / R = (I^2)R = VI
HP/.00134= Watts Then Watts divided by Volts = AMPS For expample. a .75 HP electric motor running on 220VAC uses 2.544 amps .75 / .00134 = 559.7015 Watts then 559.7015 / 220 = 2.544
21.739 a 21.739 a
Electric power is measured in watts. It does not matter if it is single phase or three phase. All things being equal, for the same load, the power measured in a single phase circuit or a three phase circuit, will be the same.
I think you mean 'three phase', not 'three face'!Power factor is a function of the load, notthe generator. The power factor of the load can be determined from its true power (expressed in watts) divided by its apparent power (expressed in volt amperes). For a balanced load, this can be done by manipulating the following equation:True Power = 1.732 VL IL x power factorWhere VL and ILare the line voltage and line current.For an unbalanced load, it is rather more complicated than can be explained in this forum.