Yes. But that is true only if the 100 digits do not include 0. Or, if 0 is included, then you consider "0n0" to be a three digit number. Most people would consider is to be a 2-digit number.
189 palindromes.
198 palindromes.
There are 186 palindromes between 40 and 10,000.
40
There are 40 palindromes that are divisible by 25
90000. With 10 digit palindromes, the last 5 digits are the same as the first 5 digits in reverse, eg 12345 54321. So it comes down to how many 5 digit numbers are there? They are the numbers "10000" to "99999", a total of 99999 - 10000 + 1 = 90000.
189 palindromes.
198 palindromes.
There are 186 palindromes between 40 and 10,000.
40
There are 40 palindromes that are divisible by 25
There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.
10000x10000=100000000
11000
There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.
If initial zeros are considered acceptable digits, it is 00001. Otherwise, it is 10000.
There are 20 integer palindromes between 10,000 and 99,999 that are divisible by 25.