No... the source does not have the required capacity. The device (sink) would ask for more current which the source will not be able to provide.
Do not use this source-sink pair.
The voltage across a DC device that draws 2A and consumes 12Wh/h is 12/2 or six volts.
No, underpowering will not "power" the device, it will not run. You must get an adapter that is 6V and (2A or higher) will be ok as well.
If you mean: 4a-3 = 2a+7 then the value of a works out as 5
Yes, a DC adaptor outputting 12V and 2A will work for a device that requires 12V and 1.5A. The adaptor can provide up to 2A, which means it can supply the necessary current without overloading. Just ensure that the voltage matches (12V) and the polarity is correct for safe operation.
Yes, you can use a 5V 2A power supply for a device that requires 4.5V and 1.5A, but you need to be cautious. The voltage is higher than what the device requires, which could potentially damage it. It's best to use a power supply that matches the voltage specifications of the device, or to use a voltage regulator to step down the voltage to 4.5V. The 2A rating indicates that the power supply can provide more current than needed, which is fine as the device will only draw the current it requires.
The adapter's voltage must match that of the device, and its current-rating must exceed that of the device. So the answer is yes.
No
Yes, there will be no problem with this adapter. The 1 amp device will only be drawing half of what the adapter can produce.
Let's solve this equation together, friend. To isolate b, we can start by subtracting 2a from both sides of the equation. This will leave us with b equals P minus 2a. Remember, there are many ways to approach a problem, and it's all about finding the one that works best for you.
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
If you mean: -4a+5-2a-9 = 44 then 'a' works out as -8 Check: -(4*-8)+5-(2*-8)-9 = 44
2a+2a-7b+7b =4a