yes just x32 OS cannot
Are you using a 32 bit or 64bit OS? 32 bit only supports a maximum of 4 GB of ram
You can use either a 32bit or 64bit operating system (OS) for 4GB of RAM. 4GB of memory is the limit a 32bit OS can handle, this includes any memory that your graphics card has, so your computer may recognise only 3.5GB of RAM if you have a 512MB GPU. You will need a 64bit os that will use all of the ram.
32-bit OS has many limitations. It can not use full 4 GB RAM or more that that. It can utilize only 3.7 GB of RAM.
a 32-bit OS is limited to 4 Gigabytes of ram
depends on your motherboard and how much is best depends on if you are running a 32 or 64 bit OS. most people have a 32 bit OS, which can support a maximum of 4 GB of ram. in general DDR3 ram with the most capacity (ie 2GB) and speed (ie 2133 MHz) would be best
2 GB of RAM 160 GB HDD
Usually 4 GB is the maximum in most recent consumer computers -- although 32 bit Windows can recognize only 3.5 GB or less of the total. Some machines (Intel i7 based machines, Macs, Xeon based workstations) can take more than 4 GB of RAM if they have a 64 bit operating system (Windows XP64, Vista 64, OSX, Linux) but the motherboard memory controller must be able to support RAM over 4 GB as well as the OS.
Absolutely !
RAM is partly dependent on your system's avalible slots. however, usually it's a case of the capacity of your OS for example, I have 4GB(2x2GB) Ram in my PC - on XP it reads 3.25Gb of RAM - this is as XP can only handle around 3Gb where as vista can handle 4 and x64 operating systems can handle much more
Mac os is compatible with all the intel hardware computers which have 40 gb of free space and min 2 gb of ram but i suppose if you want to run it smoothly you should have atleast 4gb of ram This procedure is popularly known as HACKINTOSH.
768 MB RAM is good for Windows XP only. If you want the more recent Vista or 7, maybe try upgrading to at least 1 GB.
XP will only recognize up to 3 GB of RAM. However how much RAM your computer can hold is dependent on the model not the OS.