Yes of course Ca(OH)2 could replace NaOH to have the following reactions
Ca(OH)2 + SO2 = CaSO3 + H2O
CaSO3 +1/2 O2 + 2H2O = CaSO4.2H2O
40 grams, this is the 1M NaOH standard laboratory solution.
it depends on the concentration of NaOH, pepsin, buffer used, ... that cannot be answered in that way...
NaOH
NaOH can be used in this situation.
It would be acidic rather than basic. Beyond that, you'd need to provide additional details.
40 grams, this is the 1M NaOH standard laboratory solution.
it depends on the concentration of NaOH, pepsin, buffer used, ... that cannot be answered in that way...
NaOH
NaOH
150 M NaOH = 150 mole / liter 20.0 mL = 0.0200 L 150 * 0.0200 = 3 moles
NaOH can be used in this situation.
It would be acidic rather than basic. Beyond that, you'd need to provide additional details.
alot
NaOH
NaOH
NaOH is required promote Aldol and dehydration at the end of the reaction. Moreover, the percentage of NaOH is less as greater %age would promote Cannizaro reaction.
Methyl orange