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yes it can, the equation involved is :

force (f) = mass(m) * (velocity(v)^2 / radius(r))

say mass = 1 kg, radius = 1 m

then:

424 = 1 * (v^2 / 1)

velocity required to produce this force:

v = sq. root ((424 * 1) / 1)

v= 20.6 metres / sec

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Q: Can a ball moving in a circle have 424 N of net force acting on it.?
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Inthe kicking force, kinetic energy is acting on the ball together with Gravitational Potential Energy. Whereas the part where aother force is acting on iit while the ball is not moving is alsoocontrolled by gravitaitional potential energy.


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Picture a ball on a string being whirled about the head of an experimenter. If the string breaks, the centripetal force disappears. The ball leaves on a tangent path form its (previous) circular path. Yes, it's that simple. The string provided centripetal force, by virtue of its tensile strength, to the ball to keep that ball moving in a circle. When the string broke, there was no force left to accelerate the ball "in" and keep it moving in an arc.


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The roulette ball stays in motion due to centrefugal force. Since the ball is moving fast it "wants" to just go straight (Newton's 1st law) but the contact force of the metal track exerts an inward force that keeps it moving in a circle. Eventually, as the ball loses momentum, the force of gravity will be greater and the ball will then fall into a pocket.


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