0
yes it can have
What else can I help you with?
Can a byte store a word?
yes it can have
Why memory is divided in even and odd banks in 8086 microprocessor?
in 8086 there is 20 bit address bus,so it can address 1,048,576 address. At each address we can store 8 bit address (1-byte)but if want to write a word(16-bit)into a memory segment to store data in byte form then we write the data in two consecutive memory address which are even(low) and odd(high) memory.
How many bytes are required to store the word SUMMER in computer memory?
A letter is stored in binary on a computer. The word summer in binary is written as: 011100110111010101101101011011010110010101110010. That's 48 digits. There are 8 bits in 1 byte, thus 48/8 = 6. So 6 bytes are used to store summer. On modern computers, each character in the English alphabet is represented by a byte. Therefore the word SUMMER takes up 6 bytes of memory.
What is a difference between register and a memory location?
difference between register and memory location
What is memory word size required in an 8085 system?
In an 8085 system, the memory word size required is 8 bits. This means that each memory location can store 8 bits or one byte of data. The 8085 processor accesses memory locations using these 8-bit memory addresses to read or write data during program execution. The memory word size of 8 bits allows the 8085 system to handle data in small, manageable chunks efficiently.
What is the name of the storage location in the computer's memory?
Depending on the architecture of the computer one addressable memory location might be called a word, a character, a parcel, a decimal digit, a byte, etc.
What are the four units of measure for computer memory and storage not including the byte?
Name 4 memory units in which memory of a storage device is measured not includin byte?
What is a unit of computer memory?
KB = 1024 Bytes MB = 1,048,576 Bytes Byte = 8 Bits Note K can sometimes = 1000 and M can = 1,000,000 It depends on whether your talking about Hard Drive storage (1000) Download speeds (1000) or RAM memory(1024) . Than RAM is different because it uses a Binary value that is sometimes rounded out to a Decimal value
How can you arrange bit byte word nibble in ascending order?
bit, nibble, byte, word
If A word on a little-endian computer has the numerical value of 3 If it is transmitted to a big-endian computer byte by byte and stored there with byte 0 in byte 0 and so on what is its numerica?
In a 32-bit word, the decimal value 3 has hex value 0x00000003. Laid out in memory in a little-endian computer, it is 0x03, 0x00, 0x00, 0x00. If you move that to a big-endian computer without reversing the byte order, you get 0x03000000, which is decimal 50,331,648. The correct big-endian representation should have been 0x00, 0x00, 0x00, 0x03.
How do you calculate the size of the structure?
The Structure size can be calculated by adding the memory requirements of each individual structure members. This is applicable for the word alignment of one byte. The word alignment of one byte can be set by the following statement#pragma pack(1).AnswerDon't try to calculate anything, use sizeof.
Why the size of class in oops is 1 byte without datamember?
The size of an empty class is not normally 1 byte, actually. It will usually be equal to the word size defined by the platform it is running on (often 2 or 4 bytes). This is because the word size is usually used as a memory address size and an empty class still needs to point to some location in memory (even if that location stores no data).
