Can a programmer catch an error in java code?

Answer 1

Yes or course...

Of course,java provides the try-catch construct to handle this proplem.You just need to throw out you unconventional codes in try construct and handle it in catch construct.Here is an example:

import java.io.*;
import java.io.IOException;
import java.io.InputStreamReader;
public class Sorter{
public static void main(String args[])throws NumberFormatException,IOException,NopositiveException
{
try{
PutIn in=new PutIn();
in.Order();
in.Out();
}

catch(NopositiveException e)//handle user defined exception

{
System.out.println(e.toString());
}
catch(NumberFormatException e)//handle java's exception
{
System.out.println("it's not number!");
}
}

}
class PutIn
{
int number[]=new int[10];
PutIn()throws IOException,NopositiveException
{
String str[]=new String[10];
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
for(int i=0;i<10;i++)
{
str[i]=br.readLine();
if((Double.parseDouble(str[i])-(int)Double.parseDouble(str[i]))!=0)//if it si a int type
{
NopositiveException exception=new NopositiveException(str[i]);
throw exception;//throw exception
}
else
number[i]=Integer.parseInt(str[i]);
}
}