Yes, in many ways. Magnetic Anomaly Detector (MAD), dipping sonar, and sonobuoys are common.
I would suggest you check out http://www.acig.org/artman/publish/article_491.shtml for more.
The volume of the submerged object.
a submerged object displaces liquid which is equal to its volume
Submerged density is the density of an object when it is immersed in a fluid. It takes into account the volume of the object that is submerged in the fluid. This can be calculated using the formula: (density of object * volume of object) / (volume of object - volume of displaced fluid).
The buoyant force on a submerged object depends on the volume of the object. It is equal to the weight of the fluid displaced by the object, which is determined by its volume. The weight of the object itself affects the net force experienced by the object when submerged.
The amount of fluid displaced by a submerged object is equal to the volume of the object that is submerged. This is known as Archimedes' principle, which states that the buoyant force acting on an object in a fluid is equal to the weight of the fluid displaced by the object.
FALSE
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.
Length times Width times Height. Archimedes used a "bathtub", and submerged the object to see what volume of water was displaced.
You will find that such an object will weigh its weight on land minus the weight of the water it displaceswhen submerged. It doesn't seem possible, but it is true. This kind of result is called 'counterintuitive'.
greater than
The milliliters of a completely submerged object is equal to the milliliters of water displaced. This is in line with Archimedes' principle, which states that the volume of water displaced by an object is equal to the volume of the object submerged.