Yes, at room temperature bromine reacts with phenol and forms 2,4,6-tribromo phenol.
Use bromine water (Br2) or acidified permanganate (H+/MnO4-) With permanganate: add the permanganate to the alkane and no reaction will occur, add the permanganate to the alkene and you will form a diol the solution will also turn from purple to colourless. With bromine water: add the bromine water to the alkane (plus you need sunlight) and you get a substitution reaction, this is a slow reaction. Add the bromine water to the alkene and you get an immediate addition reaction (this one does not need sunlight). When bromine water reacts with an alkene it is decolourised, the reddish brown bromine water turns from brown to colourless. This is because alkenes are unsaturated and contain a carbon to carbon double bond. If you did the bromine water test in a dark place say a cupboard then the alkene would decolourise but the alkane wouldn't because it needs UV/sunlight in order to react. in practice the cupboard is not necessary as the speed of decolourisation is so much faster with the alkene.
Two magnesium atoms would be needed to react with one bromine molecule. Magnesium has a +2 oxidation state, while bromine has a -1 oxidation state. This means that two magnesium atoms are needed to balance the charges when reacting with one bromine molecule.
Bromine in chloroform typically tests for the presence of alkenes or aromatic compounds. Bromine will react with the double bond or aromatic ring to form a dibromo compound, resulting in a color change from red-brown to colorless. This test is commonly known as the bromine test.
The question is not very specific, so there is more than just one answer, but I'm assuming you are referring to a radical bromination of an alkane (ethane) versus an electrophilic bromination of an alkene (ethene).Br2 in the presence of a radical initiator (such as light or heat) will add to ethane to form 2-bromoethane as the major product in a radical mechanism. This goes through an initiation step (forming 2 bromine radicals), followed by propagation to the alkane (forming a secondary ethyl radical), followed by a termination step. The termination step leading to the product is one where another bromine radical joins with the ethyl radical.In the absence of light or heat, bromine cannot react with an alkane, but it can react as an electrophile with an alkene. In this type of reaction (electrophilic addition to an alkene), the ∏-bond (double bond) on ethene attacks a bromine atom (from Br2) and kicks out a bromide (Br-). The bromine that was just added forms two bonds (one on each carbon of the double bond), giving a three-membered C-Br-C ring called a bromonium ion (since the bromine atom now has a positive charge). The bromide that left before can now attack the backside of the bromonium ion, opening the 3-membered ring, and adding anti to form a dibromoalkane (1,2-dibromoethane in this example). This reaction is stereospecific because in the major product the bromine atoms will always add anti (to the opposite side) on the alkene.
One way to distinguish between ethene and ethyne is by performing a bromine water test. Ethene will decolorize bromine water, turning it from orange to colorless, while ethyne will not react with bromine water. This test takes advantage of the unsaturation in ethene that allows it to quickly react with bromine.
Ethene can react with Bromine water - turns colourless
Bromine water test is used to show that ethene is unsaturated. In the presence of ethene, the red-brown color of bromine water disappears due to addition reaction with ethene, indicating its unsaturation.
Yes, however it doesn't require it either to react. ethene+bromine water→1,2-dibromoethane Ethane reacts with bromine only in the presence of UV forming bromoethane and hydrogen bromide.
Methane and bromine cannot react without the presence of sunlight or U.V light because of lack of energy which is usually supplied by the U.V light to break the bromine molecules to free radicals for the reaction to occur.Hope my answer helped.ABUAD
Oh, dude, it's like this - polyethene is like the chill, laid-back version of ethene. It's already in a stable, happy relationship with itself, so it's not looking to get involved with bromine water drama. Ethene, on the other hand, is out there on the prowl, ready to react and cause a scene. So yeah, polyethene's just like, "No thanks, bromine water, I'm good."
Organic compounds called Alkenes turns Bromine to colourless from orange-ish without sunlight as a catalyst. Alkanes however require sunlight to react.
How does the human body react to long periods without sunlight?
Ethanol does not react with bromine.
In the absence of sunlight, methane (CH4) will react with bromine (Br2) to form bromomethane (CH3Br) and hydrogen bromide (HBr) as products. The balanced chemical equation for this reaction is CH4 + Br2 -> CH3Br + HBr.
Bromine does not react with air because it is not possible. It is a non reactant element.
Yes, bromine will react with sodium. When bromine comes in contact with sodium, they will react to form sodium bromide, a white solid compound. This reaction is a redox reaction where bromine gets reduced and sodium gets oxidized.