Organic compounds called Alkenes turns Bromine to colourless from orange-ish without sunlight as a catalyst. Alkanes however require sunlight to react.
In the absence of sunlight, methane (CH4) will react with bromine (Br2) to form bromomethane (CH3Br) and hydrogen bromide (HBr) as products. The balanced chemical equation for this reaction is CH4 + Br2 -> CH3Br + HBr.
Methane and bromine cannot react without the presence of sunlight or U.V light because of lack of energy which is usually supplied by the U.V light to break the bromine molecules to free radicals for the reaction to occur.Hope my answer helped.ABUAD
The reaction between ethane and bromine in the presence of sunlight results in the substitution of hydrogen with bromine. This leads to the formation of bromoethane (ethyl bromide) as the product. This kind of reaction is an example of a free radical halogenation reaction.
One simple chemical test to distinguish between benzene and hexane is the Bromine test. Benzene will not react with bromine in the absence of a catalyst, while hexane will readily react with bromine to form a colorless product.
No, hexane does not react with bromine in the absence of ultraviolet light or intense heating. Bromine typically requires the presence of such conditions to undergo a reaction with alkanes like hexane.
In the absence of sunlight, methane (CH4) will react with bromine (Br2) to form bromomethane (CH3Br) and hydrogen bromide (HBr) as products. The balanced chemical equation for this reaction is CH4 + Br2 -> CH3Br + HBr.
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Sunlight is used in the bromine water and iodine solution tests to provide the energy needed for the reactions to occur. The UV light in sunlight promotes the oxidation of bromide ions to form bromine and the oxidation of iodide ions to form iodine, which are key reactions in these tests.
The reaction between methane and bromine in the presence of sunlight results in the substitution of one hydrogen atom in methane with a bromine atom, yielding bromomethane (CH3Br). The equation for this reaction is: CH4 + Br2 → CH3Br + HBr.
Methane and bromine cannot react without the presence of sunlight or U.V light because of lack of energy which is usually supplied by the U.V light to break the bromine molecules to free radicals for the reaction to occur.Hope my answer helped.ABUAD
Leaves appear green due to the presence of chlorophyll, a pigment that absorbs sunlight for photosynthesis. Even in the absence of sunlight, chlorophyll can still reflect green light, which is why leaves continue to appear green.
The reaction between ethane and bromine in the presence of sunlight results in the substitution of hydrogen with bromine. This leads to the formation of bromoethane (ethyl bromide) as the product. This kind of reaction is an example of a free radical halogenation reaction.
Sunlight wouldn't be enough energy to carry out the reaction between n-hexane and bromine. The energy source, however, may have been written has "hv" as a way to describe the radiation or high-wavelength energy for the reaction, which is possible in a more controlled environment. In this scenario, the reaction between n-hexane and bromine is a bromination reaction--generation of a bromine radical and attaching one or more bromine molecules to hexane. It is more likely that it will attach to a secondary carbon rather its primary, and its location of attachment between the available secondary carbons would be a mixture.
One simple chemical test to distinguish between benzene and hexane is the Bromine test. Benzene will not react with bromine in the absence of a catalyst, while hexane will readily react with bromine to form a colorless product.
No, hexane does not react with bromine in the absence of ultraviolet light or intense heating. Bromine typically requires the presence of such conditions to undergo a reaction with alkanes like hexane.
Yes, plants can absorb water in the absence of sunlight. Water absorption occurs through the roots and is essential for nutrient uptake and maintaining turgor pressure in plant cells. Sunlight is needed for photosynthesis, but water is absorbed regardless of light availability.
Bromine diffuses faster in a vacuum because there are no other gas molecules to impede its movement. In the absence of other gas molecules, bromine is able to move freely and quickly through the vacuum.