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Can magnetic poles be isolated

Updated: 12/20/2022
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14y ago

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This question is conventionally said to be NO. Maxwell's Equations to define Del.Bv =0! This is a definition of the magnetic B field as circular field with no poles.

This is another example of science not recognizing quaternions in Physics. The magnetic field has a scalar part and a vector part:

E= Es + Ev = c(Bs + Bv)

The relation E=cB was the key to Maxwell identifying Light with Electricity. This means if there is a scalar Es there is a scalar Bs= Es/c and if there is a scale Es there is a scalar Ds = Es/zc= epsilon Es.

All the elxctromagnetic fields are related by

E=cB=zH=czD giving B=zD!

Maxwell's Equations are not correct in this matter. The real definition is :

dBs/dr=Del.Bv

cDBs/dr = cDel.Bv

dEs/dr = Del.Ev

dDs/edr = Del.Ev

Del.Ev is not idnetically zero then Del.E/c is not identically zero unless dDs/dr is identically zero/ and that is not true for all Ev. Del.Ev = rho/epsilon in many cases where there is charge density.

The electromagetic fields are related by E=cB=zH=zcD thus B=zD where z is the free space impedance Constant z=375 Ohms.

Thus dBs/dr = dzD/dr= zdDs/dr = zrho where rho is the charge density. this means that

in general zdDs/dr= Del.Bv so Del.Bv is zero only when there is no charge density, otherwise if there is a charge density there is a "magnetic pole", zdDs/dr= zrho.

This would mean for an atom, the nucleus has a charge density and a magnetic field. A collection of atoms may have a charge density in a certain direction but not overall.

Magnetic poles exist in this definition and Maxwell's Equations represent a limited condition. There are no poles under Maxwell's Condition, that there is no charge density.

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