Constant velocity gives zero acceleration, force is mass times acceleration, thus if acceleration is zero then force is zero and equilibrium is zero force. Equilibrium = zero force :0=f=ma=mdv/dt = m0 when velocity is constant dV/dt=0.
Rotational Equilibrium is analogous to translational equilibrium, where the sum of the forces are equal to zero. In rotational equilibrium, the sum of the torques is equal to zero. In other words, there is no net torque on the object.
By the definition of mechanical equilibrium, Yes. Because the sum of forces is equal to zero, it can be seen from the equation F=ma that the total acceleration on the object must be zero in order for the equation to hold. The mass is only a constant in this equation in this situation, and remains unchanged.
when it is at rest, or in constant uniform motion with net force and moment of zero (no acceleration)
the sum of all forces acting on an object should be equal to zero the sum of all forces acting on an object should be equal to zero
If the equilibrium constant is zero, the reaction canNOT (will NEVER) reach equilibrium, it can not react back because all products are 'removed' (= concentration is zero).
The two conditions of equilibrium are: 1. Concurrent Equilibrium the sum of vector forces through a point is zero. 2. Coplanar equilibrium, the sum of forces in a plane is zero and the sum of the torques around the axis of the plane is zero. These two conditions are similar to Ohms Laws in Electricity: Ohms Node Law the sum of the currents at a node is zero and Ohms Voltage law, the sum of the voltages around a loop is zero. These equilibrium conditions reflect the Quaternion mathematics that controls physics. Quaternions consist of a scalar or real number and three vector numbers. Equilibrium is the Homogeneous condition of a quaternion equation: the sum of the scalars or real numbers must be zero AND the sum of the vector numbers must also be zero. Thus there are TWO Conditions for Equilibrium. However if we were to use quaternions as nature does, then Equilibrium would be simplified to the zero quaternion condition.
if the net force is equal to zero then the body is said to be in equilibrium.that is the forces acting o n the body are balanced.In this equilibrium state Fnet is equal to zero.
Constant velocity gives zero acceleration, force is mass times acceleration, thus if acceleration is zero then force is zero and equilibrium is zero force. Equilibrium = zero force :0=f=ma=mdv/dt = m0 when velocity is constant dV/dt=0.
No
The Condition of Equilibrium, Force equal zero, is the condition of an object at rest or moving at constant velocity. Non-Equilibrium Condition, Force is not zero, is the condition for an object to move with increasing velocity.
Rotational Equilibrium is analogous to translational equilibrium, where the sum of the forces are equal to zero. In rotational equilibrium, the sum of the torques is equal to zero. In other words, there is no net torque on the object.
The information an acid or base equilibrium constant gives is that the acidity and base levels are equal to the equilibrium constant multi[plied by the water concentration.
By the definition of mechanical equilibrium, Yes. Because the sum of forces is equal to zero, it can be seen from the equation F=ma that the total acceleration on the object must be zero in order for the equation to hold. The mass is only a constant in this equation in this situation, and remains unchanged.
0. An object in equilibrium has constant velocity, which makes its acceleration 0. Since net force=mass times acceleration, this would make the net force zero. Note that there could be multiple forces acting on the object, but since it is in equilibrium they would have to be equal and opposite in direction, to cancel all of the forces out. This would make the net force zero.
A system has a G equal to zero means it has reached equilibrium .
No.