F[net]=ma ([net] force = mass X acceleration). It is possible. While mass can't be negative, acceleration depends on which direction you're measuring to be positive. If you're acceleration is negative, so is your net force. For example, if you're traveling 60 mph southward, and apply the breaks at -4.7 m/s/s, to find the net force (This works because your car technically would have been in equilibrium had it stayed at 60 mph in the same direction), you would simply multiply your rate of acceleration by the mass of your vehicle, say 1000 kg, which would give you a net force (all forces cosidered) of -4700N southward. At the same time, this could be taken as positive 4700N northward; hence it's directionally dependent. But, long story short, yes; it is possible to have a negative net force, because force is a vector (Includes direction and quantity).
Hope this helps!
- Fellow physics student
It can negative. if u get -2 N it means that the force is going to the opposite direction.
No, but its direction can.
Take north to be the positive direction, and south to be the negative direction. Net force = 13N + (-17N) = -4N Net force = 4N to the south.
If the 10N force is positive, meaning to the north, then the 5N south would be negative, and the net force is 10N + (-5N) = 5N to the north.
This would be known as the net-force.
Add the different forces together to find the net force. For example, if you have a force of -5N acting on an object and another force of 8N acting on that object, the net force is 3 N.
We are assuming that the forces are opposite of each other, meaning that they will cancel out. Net force is simply 39-22 (or 17 newtons).
Take north to be the positive direction, and south to be the negative direction. Net force = 13N + (-17N) = -4N Net force = 4N to the south.
It would be in the negative direction as well. Newton's Second law states that the acceleration of an object directly depends on the net force given to that object.
If the 10N force is positive, meaning to the north, then the 5N south would be negative, and the net force is 10N + (-5N) = 5N to the north.
No , it is less than -7N force , Negative sign with a 7 N force tells us that it is acting in a direction opposite to that of motion of the body or ,.......
It would be in the negative direction as well. Newton's Second law states that the acceleration of an object directly depends on the net force given to that object.
This would be known as the net-force.
Add the different forces together to find the net force. For example, if you have a force of -5N acting on an object and another force of 8N acting on that object, the net force is 3 N.
We are assuming that the forces are opposite of each other, meaning that they will cancel out. Net force is simply 39-22 (or 17 newtons).
By adding a positive force to a negative force and determining which side has a greater strength will determine the net force.
You must first choose which direction you shall call positive, thereby the opposite direction shall be negative. Then you add these two values together to get your answer, the total net force.
Balanced forces means the net force is zero, but net force can also be positive or negative numbers. If I pull a block with a force of 10N to the right, and you pull it with a force of 10N to the left, the net force on the block is zero, thus balanced forces. If I start to pull with a force of 20N to the right, but you still pull 10N to the left, the net force on the block is 10N to the right, thus causing acceleration of the block to the right, thus unbalanced forces
The net force is the sum of all the positive and negative forces. Force F' is a four dimensional number F'=[fr , F] = fr + Ifx + Jfy + Kfz =|F|(cos(f) , Fsin(f)], this is a quaternion or for short a quat!. A' + B' forces = [a, A] + [b, B] = [a + b, A + B] is the net force of A and B. A' - B' = [a, A] + [-b, -B] = [a-b, A - B] is the net force of A' - B'.