no because L cannot equal n. L = (n-1)
Quantum numbers specify the orbitals in an atom. The set of numbers that cannot occur is n=3,I=3, m(sub)I=2 because there are no F-orbitals.
(2,1,-1,-1/2)
Pauli's exclusion principle
4, 2, -2
Then there are many modes (the set of data is multimodal).
It is the set of numbers which occur the most frequently
(3,2,-1,-1/2)
Quantum numbers are a set of 4 imaginary numbers which explain the position and spin of electrons in an atom it can not explain an atom as a whole Iodine has 53 electrons so there are 53 sets of quantum numbers for Iodine.The above is correct. Assuming you meant to ask for the quantum numbers for the last electron added to Iodine, that would be n=5, l=1, m=0, s=1/2.
Assuming you mean the set of quantum number describing the VALENCE electrons of aluminum, they would ben = 3l = 1ml = -1s = +1/2Of course, since Al has only 1 p electron, ml could also have been 0 or +1 and s could have been -1/2
No. The mode is the number that occurs most often is a set of numbers. If there are two numbers that occur the most in a set and they both occur the same amount of times, then they are both considered to be modes. Ex: What is/are the mode(s) in the following set of numbers? Set: 3 6 7 4 7 0 4 7 2 1 5 6 8 3 8 0 9 3 Answer: the modes are 3 and 7; they occur the most amount of times (3 in this case) and they both occur 3 times
10 electrons.The angular momentum quantum number is l (small L). This quantum number is dependant on the principal quantum number, and has values, 0 1,2 ..(n-1), where each value of n refers to a subshell known to chemists as followsn= 0, s orbital; n=1, p orbital; n= 2, d orbital; n= 3, f orbital.So we are looking at the d orbitals.There are five d orbitals, with magnetic quantum numbers running from -l to +l, that is -2, -1, 0, +1, +2Each of these can hold 2 electrons (with spin quantum numbers -1/2, +1/2)So we have 10 electrons that can have pricipal quantum numbers of 4 and angular monmentum quantum number of 2.
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