Yes, there is no problem in transmitting capacitive VARs if they occur.
Same
Power factor is determined by the nature (resistive, inductive, capacitive) of a load, not whether it is a low load or a high load.
Follow the secondary wires, and see where they lead. It could be a doorbell transformer. It could be an old telephone (Trimline? Princess?) power transformer - check yellow and black in that case.
When looking at power factor, it is the ratio of watts (true power) to VA. The power factor is how we measure power systems. A person with a low power factor like .26 will have a higher electricity bill.
By definition, the terms 'leading' and 'lagging' refer to what the load current is doing with respect to the supply voltage. So, for a 'lagging power factor', it is the current that is lagging.
power factor depends on the load being fed if the load is entirely resistive power factor will be unity ..if the load includes an inductor or capacitpr due to phase displacement between v and i the pf will be lag or lead respectievly
The Magna Carta was the key factor in Europe that lead to limiting the power of government.
1st make sure the power is turned offDisconnect one lead on primary side of transformer and using an ohm meter check for continuity. You will probably get a low ohm reading if you get no reading the windings are broken and transformer is no good2nd test using ohm meter again check for winding to ground you should get no reading. If you get a ohm value the transformer is shorted to groundRepeat these tests on secondary sideWith power on and fuse removed with a voltage meter check for power on secondary sideIf it is okay turn off power and install fuseIf fuse blows again check for shorts in circuitRemember to be careful when power is turned on
Probably mans greed and thirst for power and domination.
using highly inductive loads may lead to reduction in the power factor. or consumption of unappreciable amount of power also results in the same. methods to improve PF . using synchronous condensers using capacitor banks using ow inductive loads
When there is an inductive element in the circuit, the current lags behind the voltage. an ideal inductor will make the current lag behind the voltage by 90 degrees..a capacitive element on the other hand will make the current lead the voltage (ideally by 90deg). That's why capacitors in parallel with the system are used a lot for power factor correction
that is to reduce the cost of the power plant.... Improving power factor(increasing the ration active/apparant power morethan 0.8) will increase the efficiency of uer system. Improving power factor denotes eleminating the recative power(which do no average work).... If u have more capacitive parts in uer system, the power you may need be really high when the capacitor is charging. But as it is in an a.c. system, used energy will be released and hence the average energy consumption of the cap is null. As in one instance iot absorbes energy, the electricity distributers must be able to generate such an high power which will incrrease their cost(eventhough the absorbed energy will be released)!!! Just by reducing the the reactive power, you can reduce the enery absorption. However to do so, you may have to use caps/inductors whcich will cost you a lot. Generally, electricity distributors say, "You must not reduce uer power factor than 0.8"... In some countries, distributors pay for the factries if there power factor is higher than a cirtain value(0.95).... -R-