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Can we use the equation of kinematics to find two heights attained by a body projected upwards which any velocity?
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How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
A cyclist is traveling at an initial speed of 10 ms She accelarates at a rate of .500 ms find her final speed after 9 s?
Her final speed is 14.5 m/s. The kinematics equation v = at + v0 will be useful here. Note that t is the time measured in seconds, a is the acceleration, v0 is the initial velocity, and v is the velocity after t seconds (the final velocity). We are given that v0 = 10 m/s, a = 0.500 m/s2, and t = 9 s. Using the above kinematics equation we get v = (0.500 m/s2)(9 s) + 10 m/s = 14.5 m/s. Since speed = |velocity|, then her final speed = |14.5 m/s| = 14.5 m/s.
How do Vectors and kinematics apply in medicine?
D, displacement, X=X0+V0T+0.5AT^2 V, velocity, V=V0+AT A, acceleration
What is the equation for velocity approaching that the speed of light?
The equation isv ≈ c
If an object is accelerating what equation relates the distance traveled by that object to the initial velocity final velocity and time?
Final velocity = Initial velocity +(acceleration * time)
How do you find the initial velocity given only the distance and the time traveled?
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
What is rotational kinematics?
Rotational kinematics is the same as linear kinematics but with objects in rotation. All of the linear kinematic equations that you learn for velocity and acceleration can be applied to rotational kinematics except that the greek w (omega) is used for velocity and the greek a (alpha) is used for acceleration.
When can the equations of kinematics not be used?
Equations of kinematics or equations of motion can not be used when the body is not accelerating or is moving with a constant velocity.
How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
Does the color of a laser affect the velocity of the light waves projected by the laser?
does the color of a lease affect the velocity of the light waves projected by the laser?
What physical quantities are being studied in kinematics?
Distance, Displacement, Speed, Velocity, Acceleration.
An object projected up with initial velocity v attains a height h Another object projected up with initial velocity 2v will attain what height?
4h
What is the use of quadratic equation in your real life?
Chemist use the quadratic equation all the time to find concentrations in equilibrium reactions.Mechanics in physics, kinematics to be precise, use this formula to find position, time velocity or acceleration of moving objects.X = Vot + 1/2at2--------------------------------a quadratic formula
A cyclist is traveling at an initial speed of 10 ms She accelarates at a rate of .500 ms find her final speed after 9 s?
Her final speed is 14.5 m/s. The kinematics equation v = at + v0 will be useful here. Note that t is the time measured in seconds, a is the acceleration, v0 is the initial velocity, and v is the velocity after t seconds (the final velocity). We are given that v0 = 10 m/s, a = 0.500 m/s2, and t = 9 s. Using the above kinematics equation we get v = (0.500 m/s2)(9 s) + 10 m/s = 14.5 m/s. Since speed = |velocity|, then her final speed = |14.5 m/s| = 14.5 m/s.
How fast would an M and M fall from 10 stories high?
Mass of M and M not needed and 10 stories is about 30 meters. So, this equation from kinematics will do. Velocity2 = velocity initial2 + 2acceleration gravity*distance There is no initial velocity, so no need for it in the equation. V2 = 2(9.80 m/s2)(30 meters) V2 = 588 take square root each side Velocity = 24 meters per second when it hit the ground. ----------------------------------------------------------------------
How physics is related to basketball?
Well, obviously kinematics, gravity, and velocity affect basketball. Especially when you're shooting the ball.
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
