Yes, if you take 0 though 4.
Average(0, 1, 2, 3, 4) = (1+2+3+4)/5 = 10/5 = 1
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
101
The average of the two odd integers is 28. Therefore the two integers are 28-1 and 28+1, i.e 27 and 29.
0 and 1. Integers do not include decimals, where as 9% is equal to 0.09. So the consecutive integers would be 0 and 1.
For any integer n, the numbers 2n + 1 and 2n + 3 are consecutive odd integers.
There are 30 such integers.
Heading upwards from -3, the four consecutive integers are -3, -1, 1, 3.-3, -1, 1 and 3.
The integers are -1, 1 and 3.
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
Consecutive integers are integers that follow in sequence. Each number is 1 more than the previous numbers.
-1, 1, 3, 5
The smallest is -1