no, you can't kiss anyone who have std, if you really have std.
The following example demonstrates all 4 loop structures in C++. #include<iostream> int main() { int i; std::cout<<"For loop...\n"<<std::endl; for(i=0; i<10; ++i) std::cout<<i; std::cout<<'\n'<<std::endl; std::cout<<"While loop...\n"<<std::endl; i=0; while(i<10) std::cout<<i++; std::cout<<'\n'<<std::endl; std::cout<<"Do-while loop...\n"<<std::endl; i=0; do { std::cout<<i; }while( ++i<10 ); std::cout<<'\n'<<std::endl; std::cout<<"Goto loop...\n"<<std::endl; i=0; again: std::cout<<i; if(++i<10) goto again; std::cout<<'\n'<<std::endl; } Output: For loop... 0123456789 While loop... 0123456789 Do-while loop... 0123456789 Goto loop... 0123456789
well in collage about 10 years ago when i was studying to be a doctor i learned that yo can get a std if you kiss a girl that is on birth controls. They said that there is a 2% chance you can get the std aid/HIV but that is not the only std u can get . you can get a lot of std form kissing a girl that is on birth control if you kiss a girl while she is on birth control there is a 67.82% that you will end up with herpes or cancer because all the acid from the pills go in your mouth so be careful. So you have to wait until the girl is off of birth control the u have to wait until 2 months to kiss her so all the acid comes out her body form the pills.Thank you. Doctor Skillman-scrip 2
If they had a cold sore while kissing you, or they have an STD. I'd get myself checked out if I were you.
If you mean you cannot use a for loop, then use a while loop: int i=0 while( i++ < 100 ) std::cout << i << " "; std::cout << std::endl; Or a do-while loop: int i=0; do std::cout << ++i << " "; while( i<100 ); std::cout << std::endl; If these are not allowed either, use a procedural loop: int i=0; again: std::cout << ++i << " "; if( i<100 ) goto again; std::cout << std::endl; If even that is not allowed, then the only option is to hard-wire: std::cout << 1 << " " << 2 << " " << [etc] << 99 << " " << 100 << std::endl; It does seem a pointless exercise when a for loop exists specifically for counting iterations like this: for( int i=1; i<=100; ++i ) std::cout << i << " "; std::cout << std::endl;
Yes I Think Because If You Get Your Period Its Not Their Business So Kiss Them __________________________________ Of course you can! Its not as if he's gonna get an STD or anything!
#include<iostream> #include<fstream> #include<vector> #include<string> std::string get_input_file() { while (true) { std::cout << "Enter the input file name: "; std::string filename; std::getline (std::cin, filename); std::ifstream file (filename); if (file.is_open()) { file.close(); return filename; } std::cerr << "The file could not be opened.\n" << std::endl; } } std::string get_search_word() { while (true) { std::cout << "Enter the word to search for: "; std::string search; std::cin >> search; if (search.size()) return search; std::cerr << "The search word cannot be an empty string.\n" << std::endl; } } std::vector<size_t> get_offsets(const std::string& filename, const std::string& search) { std::vector<size_t> offsets; std::ifstream file (filename); if (!file.is_open()) throw std::exception("The file could not be opened."); size_t offset = 0; while (!file.eof()) { size_t pos = 0; char c; while (!file.read(&c, 1).eof() && c!=search[pos]) ++offset; while (pos!=search.size()-1 && !file.read(&c, 1).eof() && c==search[++pos]); if (pos==search.size()-1 && c==search[pos]) offsets.push_back (offset); offset += pos; pos = 0; } file.close(); return offsets; } int main() { std::cout << "Word Search\n" << std::endl; std::string filename = get_input_file(); std::string search = get_search_word(); std::vector<size_t> offsets = get_offsets (filename, search); std::cout << "The word was found " << offsets.size() << " time" << (offsets.size()==1?"":"s") << ".\n" << std::endl; if (offsets.size()) { std::cout << "Offsets:\n"; for (auto off : offsets) std::cout << off << std::endl; } }
6x8x16 has 120 mixed std and bb while 8x8x16 has 90 all std or bb and 12x8x16 has 60 all std or bb and 16x8x16 has 45 all std or bb. Hope that helps
When you kiss someone while he or she is popping, it is known as dumb kissing.
#include<iostream> int main() { int x=0; while( x++<10 ) { int y=0; while( y++<10 ) { std::cout<<std::setw(3)<<x+y; } std::cout<<std::endl; } }
6x8x16 has 120 mixed std and bb while 8x8x16 has 90 all std or bb and 12x8x16 has 60 all std or bb and 16x8x16 has 45 all std or bb. Hope that helps
Kiss marks could be the "hickeys" people get when they kiss the skin while sucking on it..
#include<iostream> #include<random> int main() { std::default_random_engine generator; std::uniform_int_distribution<int> distribution (1,9); std::cout << "Array : "; int a[10]; int* p = a; do { std:: cout << (*p = distribution (generator)) << '+'; } while (++p != a + 10); int sum = 0; p = a; while (p != a + 10) sum += *p++; std::cout << "\b=" << sum << std::endl; }