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The question is ambiguous, however one possibility is a parallel circuit, which would permit one light bulb to remain lit while the other light bulb was switched off. By contrast, if the light bulbs were connected in a series circuit, switching one light bulb off would cause both lights to go off.
When a bulb fuses the circuit is broken if it is on a serial circuit. If the bulb is on a parallel circuit, only the fused bulb will go out, any other bulb would remain lit. On a serial circuit, until the bulb is replaced by a new one, the circuit is not able to be used.
If there is a bulb, it should work.
It doesn't matter where the bulb is in respect to the battery, as long as the circuit is complete, the bulb will light up.
A: HARD TO SAY because a bulb has different resistance as it warms up
60 Watts is the amount of electrical power the bulb uses when it is switched on.
yes you can
Yes if it is a 12 volt DC bulb.
fluorescents are about 5x as efficientso a 12W will give about as much light
when a light bulb is switched on it will blown..............
When the bulb is lit it uses energy. When there is no bulb, no energy is used even if it is switched on.
28.7 c
no because it would blow up because the socket would draw 13 watt not 9 watt
Power = Current * Voltage Current = Power / Voltage Current = 60 W / 120 V Curretn = 0.5 A
current flows and we have light from bulb....
yes
no