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Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.
Use your hand to make la... so easy....
well no but you could use magic to but the average human can not make themselves invisible
Albert had low self confidence and a lot of shyness. But he did make lots of aquantences who liked what he liked.
self weight calculation of column
The hamiltonian operator is the observable corresponding to the total energy of the system. As with all observables it is given by a hermitian or self adjoint operator. This is true whether the hamiltonian is limited to momentum or contains potential.
consider the following second order diffenential x d2y/dx2+(1-x)dy/dx+ny=0 is this equation self adjoint if not self adjoint equation find p(x)and the weight funtion s(x)
Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.
Marion Cameron Gray has written: 'A boundary value problem of ordinary self-adjoint differential equations with singularities' -- subject(s): Differential equations
Donald M. Topping has written: 'The Pacific Islands' 'Jordan Algebras of Self-Adjoint Operators' 'Spoken Chamorro' -- subject(s): Chamorro language, English, Textbooks for foreign speakers
remote button may be stuck.
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No but you can make your self sound like you are
Self propelled lawn mowers have gears or chain links attached on the axles that mesh with drive gears mounted on a shaft connected to the engine crankshaft. They move by themselves at a steady speed. The rate of speed on some models can be set by the operator at slow, medium or fast depending on how fast the operator wants to walk and guide the mower at the handle bars. On steep climbs they are easier on the operator because with a normal walk behind the operator has to push and guide the lawnmower from the handlebars.
Operator overloads are intended to provide an intuitive interface to your user-defined types (classes). So just as you can add two integers together using the plus operator, you should be able to do the same with your user-defined data types. However, not all operators will make sense to all objects. For instance, if the sum of two objects cannot be easily defined then it makes no sense to provide an addition operator. E.g., fruit = apple + orange would not make any sense in the real world, but float = apple + 1.25 might make sense if the primary member of apple were its price or its weight, or some other numeric value. Ultimately, an operator must be both intuitive and predictable in order to be useful. If not, then a more self-explanatory method (function) would be better than an operator overload.
# to make it's self sleepy # to make it's self comfortable # to make it's self relaxed
self-incrimination (novanet)