No, the momentum operator in quantum mechanics must be self-adjoint in order to ensure that it generates unitary time evolution and that the associated probability distribution is conserved. Making the momentum operator not self-adjoint would lead to inconsistencies with the fundamental principles of quantum mechanics.
Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.
The critical mass theory states that a sufficient number of adopters of an innovation is needed for it to become self-sustaining and widely accepted in a society. It suggests that there is a tipping point where the momentum of adoption becomes self-reinforcing, leading to accelerated diffusion of the innovation.
When critical mass is reached, a self-sustaining chain reaction occurs, leading to a nuclear explosion in the case of nuclear fission. In social contexts, critical mass refers to the point at which a movement or idea gains enough momentum to be self-sustaining and bring about significant change.
well no but you could use magic to but the average human can not make themselves invisible
Wave is a self-sustaining medium of disturbance which does not involve transport of matter itself. A wave has a magnetic and electric field oscillating perpendicular to each other. Ex. of waves water waves, sound waves, light waves etc.
The hamiltonian operator is the observable corresponding to the total energy of the system. As with all observables it is given by a hermitian or self adjoint operator. This is true whether the hamiltonian is limited to momentum or contains potential.
consider the following second order diffenential x d2y/dx2+(1-x)dy/dx+ny=0 is this equation self adjoint if not self adjoint equation find p(x)and the weight funtion s(x)
Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.
Marion Cameron Gray has written: 'A boundary value problem of ordinary self-adjoint differential equations with singularities' -- subject(s): Differential equations
Donald M. Topping has written: 'The Pacific Islands' 'Jordan Algebras of Self-Adjoint Operators' 'Spoken Chamorro' -- subject(s): Chamorro language, English, Textbooks for foreign speakers
remote button may be stuck.
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No but you can make your self sound like you are
# to make it's self sleepy # to make it's self comfortable # to make it's self relaxed
Self propelled lawn mowers have gears or chain links attached on the axles that mesh with drive gears mounted on a shaft connected to the engine crankshaft. They move by themselves at a steady speed. The rate of speed on some models can be set by the operator at slow, medium or fast depending on how fast the operator wants to walk and guide the mower at the handle bars. On steep climbs they are easier on the operator because with a normal walk behind the operator has to push and guide the lawnmower from the handlebars.
Operator overloads are intended to provide an intuitive interface to your user-defined types (classes). So just as you can add two integers together using the plus operator, you should be able to do the same with your user-defined data types. However, not all operators will make sense to all objects. For instance, if the sum of two objects cannot be easily defined then it makes no sense to provide an addition operator. E.g., fruit = apple + orange would not make any sense in the real world, but float = apple + 1.25 might make sense if the primary member of apple were its price or its weight, or some other numeric value. Ultimately, an operator must be both intuitive and predictable in order to be useful. If not, then a more self-explanatory method (function) would be better than an operator overload.
self-incrimination (novanet)