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No, the momentum operator in quantum mechanics must be self-adjoint in order to ensure that it generates unitary time evolution and that the associated probability distribution is conserved. Making the momentum operator not self-adjoint would lead to inconsistencies with the fundamental principles of quantum mechanics.

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1y ago

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What is the commutation relation of spin operator 's' and the linear momentum 'p'?

Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.


What is the critical mass theory?

The critical mass theory states that a sufficient number of adopters of an innovation is needed for it to become self-sustaining and widely accepted in a society. It suggests that there is a tipping point where the momentum of adoption becomes self-reinforcing, leading to accelerated diffusion of the innovation.


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When critical mass is reached, a self-sustaining chain reaction occurs, leading to a nuclear explosion in the case of nuclear fission. In social contexts, critical mass refers to the point at which a movement or idea gains enough momentum to be self-sustaining and bring about significant change.


Can you make your self invisible?

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What travels along with a wave?

Wave is a self-sustaining medium of disturbance which does not involve transport of matter itself. A wave has a magnetic and electric field oscillating perpendicular to each other. Ex. of waves water waves, sound waves, light waves etc.

Related Questions

Is momentum hamiltonian operator is hermitian operator?

The hamiltonian operator is the observable corresponding to the total energy of the system. As with all observables it is given by a hermitian or self adjoint operator. This is true whether the hamiltonian is limited to momentum or contains potential.


What the second order consumer?

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What is the commutation relation of spin operator 's' and the linear momentum 'p'?

Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.


What has the author Marion Cameron Gray written?

Marion Cameron Gray has written: 'A boundary value problem of ordinary self-adjoint differential equations with singularities' -- subject(s): Differential equations


What has the author Donald M Topping written?

Donald M. Topping has written: 'The Pacific Islands' 'Jordan Algebras of Self-Adjoint Operators' 'Spoken Chamorro' -- subject(s): Chamorro language, English, Textbooks for foreign speakers


Why does garage door operator go up and down by its's self?

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Starting in Texas: $15.00hr. Experience of 5 years: $27.00hr. Experience of 15 years or more: $43.37hr.


Can you make your self laugh?

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What is the point of overloaded operators?

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To make your self look guilty?

self-incrimination (novanet)