A: NO the power output will be higher. Bridge rectifiers do not provide more voltage output it just add more power by rectifying both positive and negative voltage of the AC input
It is defined as the ratio of RMS value of output voltage to the average value of the out put voltage.
in full wave bridge rectifier, the input and out put voltages are same but in case of two diode rectifier the input and output voltages can be different as per requirement a there is a transformer in the circuit. The former is lighter and the later is heavier.
it will work as a rectifier . because the AC current to be rectified will not be effected by this change. the out put DC polarity will be changed.
A regulator is referring to a regulator rectifier which converts the ac voltage put out by the stator to dc voltage and regulates it to a consistent voltage usually 12-14 volts dc.
You reduce ripple voltage by adding a low-pass filter. In the simplest case, you put a capacitor after the rectifier. The peak voltage will be the rectifier output voltage less the forward bias of the rectifier, while the minimum voltage will depend on current and capacitance. In a more complex case, you could use an LC filter, making the peak voltage smaller. Specifics are dependent on the power and performance requirements.
A: Actually there is no changing of diodes required to get negative voltage out put the two cathode to ground if you have a load the voltage across will be negative. Electrons only flow in one direction where the measurement point are located across the load makes positive or negative.
the answer is Rectifier. it converts ac voltage into dc which can apply to the dc device
You don't have a full wave rectifier set-up. You need to use a full wave bridge set-up, and when you do, it'll put out 1.4 times the voltage of the secondary of the transformer.
Generally, the rectified voltage (DC Voltage) is less than the supply voltage (230 VAC or 110 VAC). Therefore, there is a need to step down the mains voltage to the required value before rectification. AC Voltage is denoted by the Root Mean Square (RMS) value which is equal to the peak voltage of the sine wave divided by 1.4 (square root of 2). Therefore, the out put of a full wave rectifier with a smoothening filter (say, a condenser) will be about 1.4 times the RMS value of AC Voltage. For eg. if we need 12 VDC output from the rectifier, the AC Voltage output of the transformer (which will be the input to the rectifier) should be 12/1.4 ie. 8.6 V. However, since a stabilized DC power supply will usually have some kind of a voltage stabilizer, the output of the rectifier can be higher. Therefore, the transformer output can be 12 volts RMS in this case. The DC output will be roughly 12 x 1.4 = 16.8 V and the stabilized DC voltage can be maintained at 12 V DC irrespective of small fluctuations in the AC mains voltage.
The short answer is yes, usually. If you are working with an ultra high voltage stack all bets are off. For old stereos, etc. you need to estimate the peak reverse voltage and the current requirements. If you have documentation, use it, otherwise: rule 1. PIV is 30 volts per plate, divided by the formfactor: rule 1a. Formfactors: diode=1, half bridge (center tap)=2, bridge=4. rule 1b. Use the maximum of the above and the input electrolitic working voltage multiplied by 1.4, then round up to the next standard voltage within reason (silicon is cheap). rule 2. Assume 500mA per square inch of a single plate's area. rule 3. You may need to heatsink the new rectifier, especially if the current is over a few hundred mA. rule 4. Replace the electrolitics!!!! If the unit is old enough to have a selenium, they are well past the warentee. rule 5. If the voltage is low (under 10VDC) you may need to put a small valued resistor between the rectifier and capacitor. example: a 12 plate center tapped rectifier 1.5 inches square; 12*30=360V divide by 2 =180PIV area=2.25 square inches which gives a current requirement of a little over one amp so use a 1.5A 200PIV unit.
Transformer is used to step down the voltage. Your normal supply voltage is 230V but diodes used in rectifier can't handle that huge voltage hence this voltage needs to be reduced. This is done by transformer. Transformer brings down 230V voltage to say 10V. If you are talking about step down transformer than you should know that step down transformer produces equal voltages although opposite in polarity but equal in magnitude(ie +V and -V) across both diodes. If you don't use it the voltage across one diode may be greater than voltage across other diode. Say non-center tapped transformer produces 10V across diode D1 & -8V across diode D2. In next half cycle, -10V will be produced across d1 & +8V across D2. So in first half cycle current due to forward biased diode D1(as voltage across it is greater) will be greater than the current produced due to diode D2 in next half cycle. So rectified current waveform won't be equal.The transformer is for isolation so the full wave rectifier can float free of the line hot & neutral wires. The power supply can then define its own ground node without "fighting" the line, this is also much safer for the user. Step-up, Step-down, or one-to-one transformer types are irrelevant to full wave rectifier but are selected by the needs of the application. There are solid state diodes that can handle several thousand volts if the application needs it and vacuum tube diodes that can go even higher.Full wave bridge rectifiers do not use center tapped transformer secondaries, but require the isolation the transformer provides or diodes will blow out in operation!
if you reverse the diode in a half wave rectifier, you would expect the A- Ripple to increase B- output to be less filtered C- out put polarity to be reversed D- output voltage to decrease