really sorry to this but no
Win all levels and unlock everybody then you will unlock hyper shadow
yes you can
you need to get the activation code... :/
unlock him by shagging the boss
beat the death egg as super sonic and hyper tails
You will go to an internet that is filled with cheats
its sonic but not just sonic the hedgehog but hyper sonic not dark spine not super sonic . hyper sonic can double jump and hyper sonic will run somewhere like just a sec and he can use chaos control and he transforms to diffrent colours and if he double jumps near enimie but not toutching it will just die TAKE THAT !
maybe becuz if super sonic is unlock able then shadow and super shadow should be unlock able
Cuz he flashed all 7 super emerald colours at a rate of 1 colour per nanosecond,and the rapid changing of bright colours made him super duper flashy,thus causing many kids seizures.R.I.P. Hyper Sonic Hyper Sonic required both all seven Chaos Emeralds and Super Emeralds. The Super Emeralds do not appear in any other Sonic games.
collect all the red star rings then beat all the levels in the sonic simulator
No, you can not by Hyper Sonic in Sonic Rush. For Sonic to go Hyper, he needs the 7 Super Emeralds, which Sonic Rush does not have. The Super Emeralds were only in Sonic 3 & Knuckles, so Sonic can only go hyper in Sonic 3 & Knuckles.
Yes, but he only made one appearance. If you link together Sonic 3 and Sonic & Knuckles, you get Sonic 3 & Knuckles, a game that is a combo of the two, including all levels playable as all characters (Sonic, Tails, Knuckles, Sonic & Tails), and a new set of emeralds to collect on top of the chaos emeralds. These were the hyper emeralds. Collect them all and get 50 rings to unlock hyper sonic. Hyper sonic is super sonic but much faster, and with a double jump ability. You sacrifice your super sonic ability as you pursue the hyper emeralds. There is also a secret ending to the game with all of the hyper emeralds. Sonic 3 & Knuckles is my all time favorite Sega game, and I've played all of the Sonics.