i don't know ask someone else
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If the array is static you can simply point at the first element. For dynamic arrays you can allocate a contiguous block to a single pointer which can then be subdivided using a one-dimensional array of pointer to pointers, each of which points to a one-dimensional array of pointers, each of which points to a separate object within the array. For extremely large arrays, however, it is better to split the elements into separate one-dimensional arrays, by creating a one-dimensional array of pointer to pointers first, then allocating each of those pointers to a separate one-dimensional array of pointers, each of which points to a separate one-dimensional array of objects. Either way, you must destroy all the individual arrays in the reverse order of creation.
You can't. While a string is a character array, an array is not necessarily a string. Treating arrays as if they were strings simply to swap them is madness. The correct way to physically swap arrays A and B is to copy A to a new array, C, then copy B to A, then C to B. If the arrays are the same size this is not a problem. If they are different sizes, you can only swap them if they are dynamic (not static). This means you must reallocate them. To speed up the process, copy the smallest array to C, first. A much better approach would be to point at the two arrays and swap the pointers instead.
you need strings to print any character(your name) this is not possible useing array:D
It is not possible to declare a two-dimensional array using an array of pointers in any programming language, but many programming languages support declarations of N-dimensional arrays of pointers.The exact syntax varies with the programming language, and requires support for N-dimensional arrays and pointers. In C, the following declares an array of pointer variables, each implemented as pointer to the generic type "void":void* array_1D[10];The type of the expression array_1D is "void * const."The following example expands on the previous one by declaring a two-dimensional array of "void" pointers:void* array_2D[10][20];The type of the expression array_2D is "void ** const."The last example declares a 3-dimensional array of "void" pointers, which can be seen as a 2-dimensional array of arrays of pointers:void* array_3D[10][20][30];
When you are using pointers and you don't free memory after you stoped using it, you loose certain amount of memory, which you cannot use and system cannot use either because it was reserved. When you work with huge amounts of memory like arrays you can run out of memory which will cause a fatal error.
Using this you specify that two pointers can't point on the same address
program to find maximum of two numbers using pointers
By using the library function #define A[] we can define the size of arrays
In C programming, header files are required. It doesn't matter if you are using near pointers, far pointers, both, or neither -- you still need header files. There is no connection between the necessity of header files and the pointers' size.
Accessing data by address. Some data-structures, like lists and trees, are usually implemented using pointers.
The purpose of using arrays in C is to store multiple values in one variable. Then you can make programs that use arrays like lists, printing values from multiple arrays into one line. It take memory in continues block then we can know memory location easily. We can retrieve data quickly.