6.6 x 10-9
To find the (K_b) for NH2OH, you can use the relationship (K_w = K_a \times K_b). Solving for (K_b), we have (K_b = \frac{K_w}{K_a} = \frac{1.0 \times 10^{-14}}{1.5 \times 10^{-6}} = 6.67 \times 10^{-9}). So, the (K_b) for NH2OH at this temperature is (6.67 \times 10^{-9}).
The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+
The pH of NH2OH (hydroxylamine) is neutral, around 7, because it is a weak base that partially dissociates in water to form NH2OH+. OH- ions.
NH2OH is a covalent compound. It contains covalent bonds formed between nitrogen and hydrogen atoms.
There is no such compound, NH3 is basic and somethimes written as aquous solution of NH4OH
To prepare a 0.5 M hydroxylammonium chloride solution, you would dissolve the appropriate amount of NH2OH-HCl in a specific volume of water. Calculate the moles of NH2OH-HCl needed (Molarity x Volume) and dissolve it in water to make the desired volume. Always remember to handle the compound with care due to its toxicity and reactivity.
6.6 x 10-9
The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+
yes
polar
Tetrahedral
The pH of NH2OH (hydroxylamine) is neutral, around 7, because it is a weak base that partially dissociates in water to form NH2OH+. OH- ions.
using cu and NH2OH at 250 C
NH2CH3, known as methylamine, is a weak base. It can accept a proton (H+) to form NH3CH3+, which makes it a base.
The oxime formed when butanone reacts with NH2OH exhibits the characteristic C=N bond, which imparts a significant polarity to the molecule. This polarity allows oximes to participate in hydrogen bonding and makes them useful intermediates in organic reactions. Additionally, oximes can serve as protecting groups for carbonyl compounds.
There is no such compound, NH3 is basic and somethimes written as aquous solution of NH4OH
NaNO3
Absolutely, just as stated. Examples are NH3, NH2OH, HCN, HNO3,