NaNO3
Polar Covalent
CH4 + Cl2 → CH3Cl + HCl - monohlor metan CH3Cl + Cl2 → CHCl2 + HCl - dihlor metan CHCl2 + Cl2 → CHCl3 + HCl - trihlor metan CHCl3 + Cl2 → CCl4 + HCl - tetrahlor metan
The molecular shape of HCOOH is trigonal planar, I believe...
Yes, due to the fact that the C and CL have a non-polar relationship and H2O also is very non-polar. Like dissolves like, and you get your mix.
3 Steps: Initiation: Cl--Cl bond is broken by homolytic fission. This energy is provided by UV light.Cl--Cl ----> Cl· + Cl·Propagation: 2 stagesCH4 + Cl· ----> ·CH3 + HCl·CH3 + Cl2 ---> CH3Cl + Cl·Termination: 2 radicals combine to form a moleculeCl· + Cl· ---> Cl2·CH3 + ·CH3 ---> C2H6·CH3 + Cl· ---> CH3Cl
No. There is no hydrogen bond in chloromethane.
The molecule CH3Cl has covalent bonds. In all chemical bonds, the type of force involved is electromagnetic.
Polar Covalent
CH3Cl is a polar bond. CH3Cl has a bond of three CH molecules and 1 bond of 1 C-Cl. The bond consists of a tetrahedral structural formation.
The molecule CH3Cl has covalent bonds. In all chemical bonds, the type of force involved is electromagnetic.
HCN and CH3Cl are Dipole-Dipole attractions.
Yes. Examples are methyl chloride (chloromethane) CH3Cl, carbon tetrachloride, CCl4
Methane, CH4 Methanol, CH3OH Methanal, CH2O Methyl chloride, CH3Cl
ammonia or NH3
K2S will have high boiling point than CH3Cl.
I think you have a typo in your molecular formula but CH3Cl is a polar molecule and CCL4 is a non-polar molecule
Yes.