Up to cca. 480 0C iron(II) sulfate lost crystallization water; after this temprature the sulfate is decomposed in iron oxide and sulfur oxide.
The residue obtained from heating crystals of FeSO4 (iron(II) sulfate) is Fe2O3 (iron(III) oxide) and SO2 (sulfur dioxide) gases. This is because the heating process causes the iron(II) sulfate to decompose, releasing water vapor, sulfur dioxide gas, and leaving iron(III) oxide as a solid residue.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
Iron(II) sulfate. Or the older formula name, Ferrous sulfate.
Fe(SO4)3 is Iron(III) sulfate Wrong: Fe2(SO4)3 is iron(III) sulfate.
The formula for ferrous sulfate is FeSO4.6-7H2O. (Iron Sulfate + Water) (Iron, Sulfur, Oxygen, + Hydrogen, Oxygen) No, it does not contain carbon.
That would be: Iron (II) Sulfate, with Heptahydrate, believe.
The molar mass of iron(II) sulfate heptahydrate is 278,01556.
FeSO4 ×7 H2O(s) I'm pretty sure that's the correct formula
Bluish-green (I personally would call it aquamarine or possibly teal). The link shows a picture of (solid) iron (II) sulfate heptahydrate, which is the same shade as the solution would be.
The residue obtained from heating crystals of FeSO4 (iron(II) sulfate) is Fe2O3 (iron(III) oxide) and SO2 (sulfur dioxide) gases. This is because the heating process causes the iron(II) sulfate to decompose, releasing water vapor, sulfur dioxide gas, and leaving iron(III) oxide as a solid residue.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
The heptahydrate FeSO4.7H2O is blue green.
Iron sulfate dissolves in water to make an aqueous solution of iron sulfate.
Formula: Fe(ClO3)3.7H2O
Iron(II) sulfate. Or the older formula name, Ferrous sulfate.
The iron will react with the copper sulfate, producing iron sulfate and elemental copper.
The formula for Iron(II) sulfate is FeSO4.