#include<iostream>
int main()
{
for (int i=0; i<100; ++i)
std::cout<<i<<std::endl;
}
The simplest way is probably to read the numbers into an array and then prints each element of the array starting at the last one and moving backwards.
hexadecimal dumper, which prints or displays the binary numbers of a program in hexadecimal format.
To write a program in QBasic that prints the sum of the even numbers from 1 to 20 in reverse order, you can follow these steps: DIM sum AS INTEGER sum = 0 FOR i = 20 TO 2 STEP -2 sum = sum + i NEXT i PRINT "The sum of even numbers from 1 to 20 is: "; sum This program initializes the sum to zero, iterates from 20 down to 2 in steps of -2 (to capture even numbers), adds each even number to the sum, and finally prints the result.
A restaurant prints it out using a special program
In GW-BASIC, you can print even numbers from 1 to 100 using a simple loop. Here’s a sample code: FOR i = 1 TO 100 IF i MOD 2 = 0 THEN PRINT i NEXT i This program iterates through numbers 1 to 100 and prints each number if it is even (i.e., divisible by 2).
ten
You first learn how to program in C.
It is too easy................ //Program to print numbers vertically #include<stdio.h> #include<conio.h> void main() { int last_no; int i; clrscr(); i=0; printf("Enter your last num.I will print 0 to that number"); scanf("%d",&last_no); printf("\n"); while(i>last_no) { printf("%d\n",i); i++; } getch(); } //poo.papule
/* my second program in C++ with more comments */ #include <iostream> using namespace std; int main () { cout << "Hello World! "; // prints Hello World! cout << "I'm a C++ program"; // prints I'm a C++ program return 0; }
It prints numbers at the bottom of a cheque.
void f (int* a, int len) { if (!a) return;for (int i=0; i<len; ++i) { if (a[i]%2) { printf ("%d is odd\n", a[i]); } else { printf ("%d is even\n", a[i]); } }
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