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Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
CuSO4 isn't an element.
Fe +CuSO4---------FeSO4 +Cu.
CuSO4 is the chemical formula of copper(II) sulfate.
Dont know what is CuSO. But CuSO4 is copper sulphate..
Cu is being reduced and Zn is being oxidized, hence Zn + CuSO4 --> ZnSO4 + Cu
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
CuSO4 isn't an element.
Copper sulfur oxygen
They fit the pattern: element + compound --> different element + different compound. Example: Zn + CuSO4 --> Cu + ZnSO4.
A more reactive element displace the less reactive element from a compound.Example: Fe + CuSO4 = Cu + FeSO4
Fe +CuSO4---------FeSO4 +Cu.
Zn has a lower reduction potential than Cu and so the Zn will be oxidized (lose electrons) to become Zn^2+ and the Cu^2+ in solution will be reduced (gain electrons) to become Cu(s).
No. Copper(II) sulfate has the formula CuSO4 and contains three different elements.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
HCl + CuSO4
CuSO4 . 2H2O