The field excitation could have been lost. Check the output from the voltage regulator.
Take the power output of the generator and divide it by the voltage output. I = W/E.
A good option for a generator that can output 100 kW and be easily hooked up to a house is a commercial-grade standby generator. These generators are designed to provide reliable power during outages and can be connected to the house's electrical system through an automatic transfer switch. It is important to consult with a professional electrician to ensure proper installation and compliance with local regulations.
Assuming the generator converts 90% of the mechanical power into electrical power, it has an efficiency of 90%, which means it consumes 11 kW of mechanical power under a full electrical load of 10 kW. Under no load the frictional losses will still apply, but the resistive losses in the windings will not be present. Therefore the no-load losses can be estimated as 500 watts in this conditon.
Watts = amps x volts. 1000/120 = 8.3. Assuming the oil burner motor is 120V then the generator has the ability to produce 8.3 amps. Find the amperage on the burner pump motor, if it is in this range it will work. The closer the pump amperage is to the generator output the more effect it will have on slowing the generator down on the start. Motors draw up to 300% on start up, this is what makes the generator lag when a motor is connected as a load.
1. the mitochondrion called the power generator of the cell
Efficiency is measured as the ratio of power output to power input. In this case the power input of the generator is 240V * 25A = 6000 VA however the stated losses are 900 W so the power output is 6000 - 900 = 5100W. Then the efficiency would be 5100/6000 = 0.85 or 85% efficient.
Take the power output of the generator and divide it by the voltage output. I = W/E.
EIRP (Dbm)= Output Power(Dbm)-Losses(from cables & adapters)+Antenna Gain(Db)
because DC generator generates generally generate DC power but as it has slip rings which convert it into ac output power
i think it goes from kinetic to electric + sound
The main disadvantage should be obvious - when the output voltage of the generator is used to provide field current to the generator....what happens if the output voltage sags? If the output voltage becomes depressed, the output power of the generator is compromised (becomes less and less), this in turn can cause the output to become more depressed, leading to an incrementally decreasing output capability. The main advantage is cost savings.
The input power, Pin, is reduced by different loss sources in the system. These reductions are the difference between input power & output power. The losses are: PSCL: Stator copper losses, or I2R losses Pcore: Core losses PRCL: Rotor copper losses PF&W: Friction & windage losses Pmisc: miscellaneous losses All of these losses reduce the input power. The output power is the input power minus all of the losses. Pout = Pin - PSCL - Pcore - PRCL - PF&W - Pmisc
Assuming that the output you've listed is after the power factor has been taken into account: Then 240x100 =24000w. The power factor is 0.94, therefore 24000 divided by 0.94 = 25531.915 VA. Power loss 25531.915 - 24000 = 1531.9149 VA.
First you have to understand how a generator works. Basically the excitation voltage is what varies according to generator output. Usually on a power source that has a inconsistant rpm, the excitation voltage will vary similar to a govenor in order to hold the generator output constant.
It's all to do with the conservation of energy. The output power of the transformer cannot be greater than the input power from the motor used to drive your generator! In fact, it will be significantly lower than the power of your first motor due to the efficiency of the motor, of the generator being driven by that motor, and of the transformer. So if you then try to run the original motor from the output of your transformer, the energy-losses will simply accumulate, and the motor will not be able to run!
The 0.8 Power Factor provided by generator manufacturers is not the load power factor, but it is the nominal power factor used to calculate the kW output of an engine to supply the power for a particular alternator kVA output. Alternators are therefore designed to supply their rated kVA at 0.8 lagging power factor.
Not all generators have the same output. Check the manual that came with your generator.