No. It may be close to 100% (90-something percent) but since it is not a superconductor, it emits some heat too.
They can never reach that level of efficiency.
Percent Yield
All the power absorbed by the heating element and the connecting wire is converted into heat, leading to the 100% efficiency figure.
Brightness is measured in lumens so the bulb has a brightness of 100 lumens. The electrical power the bulb uses is measured in watts. The efficiency of a bulb is expressed in the number of lumens produced per watt of electric power.
This question is ill posed. Lumen is a unit of measure for how much light comes from the lamp Watt is a unit of measure for how much energy is used by the lamp If the question were; "Which is brighter, a 2000 lumen bulb or a 1500 lumen bulb?" then the answer would be: The 2000 lumen bulb. I think the relation ship between lumen and watt is something like: Incandecent bulbs are 15w/lumen Flourecent bulbs use 40w/lumen LED bulbs are 70w/lumen The way to show the watt and lumen relationship is usually lumens (amount of light) per watt (energy consumption). This is like gas in your car (Miles or KM per Gallon or Liter). Incandescent bulbs have a maximum luminosity of 52 lumens/watt. Fluorescent bulbs range from 46 lumens/watt (CFL) to 100 lumens/watt (T5 and T8 tubes) LED bulbs range from 29 lumens/watt (older, low efficiency) to 100+ (XCree) and they are getting better.
nothing has 100% efficiency.
No. Nothing mechanical can ever have a 100% efficiency by any physical evaluation.
why is the efficiency of a calorimeter less than 100%
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.
The laws of thermodynamics imply that there will always be some loss of efficiency.
"Unity"
Cuz nuffin is purfect
(work out/work in) x 100
The machine efficiency is 35 percent (35/100).
Because there is always going to be friction, the efficiency of any machine will always be less then 100 percent.
an ideal machine
Work done = (force * distance)>Efficiency (%) = (Work done output / Work done input) * 100