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C2 (short for carbon anion) has only two unpaired electronics located inside of it. It also includes two paired electrons and this is due to the fact that when a molecule becomes an anion, it means that is have gained 2 electrons. Therefore, giving it a pair (4) electrons all together.
C2+
Yes! Since it has un-paired electrons: ) Actually C2 isn't paramagnetic. There's certain type of diagram how to determine whether molecule is paramagnetic or not. And C2 isn't. Instead C2(2+) would be paramagnetic.
I think you're talking about the massof the particle.sqrt( 1 - v2/c2 ) = 0.51 - v2/c2 = 0.25v2/c2 = 0.75v = c sqrt(0.75) = 0.866 c
You can calculate the magnitude of the displacement by using Pythagoras's Theorem. a2+b2=c2 Let a be 8, b be 6 and c be the magnitude. 8km2+6km2 = c2 64k+36km = c2 100km = c2 10km = c
C2 (short for carbon anion) has only two unpaired electronics located inside of it. It also includes two paired electrons and this is due to the fact that when a molecule becomes an anion, it means that is have gained 2 electrons. Therefore, giving it a pair (4) electrons all together.
Bromine is paramagnetic. This is because the 4p subshell has a value of 4p5. 5 electrons in a p subshell (which has space for 6), means the last electron is unpaired. The unpaired electron gives it the property of paramagnetism. Alternatively, Selenium is diamagnetic, as it has the outer subshell 4p4, meaning no electrons are unpaired.
C2+
C is 4*2 H is 1*2 For a total of 10 valence electrons
Yes! Since it has un-paired electrons: ) Actually C2 isn't paramagnetic. There's certain type of diagram how to determine whether molecule is paramagnetic or not. And C2 isn't. Instead C2(2+) would be paramagnetic.
This is called an induced dipole. Let's say HCl, which is polar (which means the electrons like to hang out on one side more than the other), comes close to a C2 molecule. C2 looks like this C=C. If the H-Cl comes close, the negative electrons in C2 will be attracted to the Hydrogen (because it's positive), just slightly. This will make C2 polar, because of its proximity to a polar molecule.
The bond order of C2 in this excited state is 1/2 (6-2) = 2. There are six bonding electrons and two antibonding electrons.
Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G
Any, it does not matter.
12c
A c2 c2 c2
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