A microwave signal at 50 GHz has waves that are 10,000 times as long as
a visible signal at yellow (600 nm) has. Therefore the yellow photon carries
10,000 times as much energy as the 50 GHz photon does.
"Visible light"
Though you can say light is made up of photons, the photons themselves are not matter, they are energy. Therefore light is actually energy. But you can still say light is made of photons.
MASER -Microwave Amplification by Stimulated Emission of Radiation.LASER - Light Amplification by Stimulated Emission of Radiation.With a LASER, we get uniform, coherent, monochromatic electromagnetic radiation of wave length in the visible and near visible range (1mm-10nm).MASERs use microwaves instead and the wavelength is longer (1mm to 1m).Since the energy of a photon can be calculated by Energy= h (Planks constant) x f (frequency) the energy in a MASER is less than that in a LASER all other things being the same.
Visible light has shorter wavelengths than microwaves. Microwaves, which might be considered the highest energy radio waves, have a longer wavelength (and a lower frequency) than visible light.
The microwave energy in a microwave oven is of a much lower frequency than light, but light is electromagnetic energy like the microwave radiation is.
The energy of visible light can be measured in organized packets called photons. These photons have discrete values of energy, meaning there is exact amounts of energy these have, and don't vary in decimal places.
Visible light
UV photons have more energy (less wavelength, higher frequency) than visible light photons. It is possible to convert photons to ones with less enery, but not the opposite.
"Visible light"
visible and invisible light
Energy of photon increases.
Higher frequency photons have more energy than lower frequency photons.
The shorter the wavelength of visible light, the higher the frequency and the greater the energy of the photons.
Yes. When electrons go from a higher energy orbital to a lower one, they release photons (ie: light).
Since photons are the basic unit of electromagnetic radiation, and since visible light is electromagnetic radiation, yes, photons within the visible light spectrum can be seen with the naked eye.
High-energy photons correspond to short-wavelength light while low-energy photons correspond to long-wavelength light. In short, the answer is red. For short-wavelengths (high energy photons) it would appear blue.
not possible, as visible light photons have less energy and ultraviolet photons need more energy. Energy can neither be created nor be destroyed. So by conservation principle ultraviolet photon as they fall on fluorescent material could give out less energetic light photons, but the converse is not possible.