The radius of the earth is 6.4 x 10^6 m. A typical orbit about 91 minutes. Show your work. Please answer this by tonight
some intersting facts are that asternouts ~ they sleep while standing~ ~they eat dry space food~ ~they can float in their spaceships~
In the near-zero gravity of Earth orbit, muscles that are ordinarily used for standing, walking, or balancing are not needed. During prolonged periods in space, astronauts have to work these muscles to keep them from atrophying (reducing in size and strength).
That works out at an acceleration of 1.63 m/s2(Presumably you meant 8.15 meters per second.)You would measure how far the rock dropped in 5 seconds. Then you could work out the final speed (or acceleration) from the "equations of motion".
Rabobank has a man standing on an orange sundial or compass
Acceleration due to gravity on Earth is 9.8 m/s2 (9.8 meters per second per second); that is, if you are not standing on something, neglecting air resistance (which creates a 'terminal velocity' and prevents you from falling too fast), your speed falling toward the earth would increase by 9.8 meters per second.
Artifical gravity is created by the outward acceleration (centrifugal force) as an object rotates around an axis of rotation. The magnitude of this outward acceleration is given by the centripetal acceleration, which is the opposing inward acceleration keeping the rotating object in circular orbit around the rotating object. In space, this would be done by rotating a space station until the centripetal acceleration is equal to the acceleration of gravity on Earth. Centripetal acceleration is given by the equation: Centripetal Acceleration = Velocity2/ Radius. As you can see, the magnitude of the centripetal acceleration is largely dependent upon the object's distance (distance) from the axis of rotation. Thus, in a space station that is fairly small (has a small radius), a standing astronaut will feel a different centripetal acceleration in his head than in his feet. Take the example of an astronaut standing up in a circular rotating space station with radius 5m and rotating at a speed of 7 m/s. At the astronauts feet (about 5 meters from the axis of rotation), the astronaut's centripetal acceleration will be given by the following equation. CA = 72/5 --> CA = 9.8 m/s2. This is roughly equal to Earth's gravitation acceleration. Now, lets see the magnitude of centripetal acceleration at the astronauts head. If the astronaut is 6 feet tall (about 1.83 meters), then the radius of rotation at the astronauts head is only 3.17 meters (5 meters - 1.83 meters). The speed of rotation will also be slower because the astronauts head, being closer to the axis of rotation, will have to complete a relatively smaller circle to complete one rotation in the same amount of time as the feet. After calculations, the resulting speed of rotation is 4.289 m/s rather than 7m/s. Thus, the centripetal acceleration at the astronauts head is given by the following equation: CA = 4.2892/3.17 --> CA=5.803 m/s2. Thus, we see a serious inconsistency between the centripetal acceleration at the feet of the astronaut and at the head of the astronaut (9.8 m/s2 at the feet and 5.803 m/s2 at the head). This difference would make the astronaut feel extremely uncomfortable and nauseated, rendering them unable to function at the high level needed for space. Instead, lets look at a large space station design. Take, for example, the Stanford Torus, a design that consists of a large 1.8 km in diameter rotating ring. At this large size, the space station would only need to rotate at one rotation per minute and at a rotating speed of 94.24 m/s in order to simulate Earth's gravitational acceleration. with a radius of 900m, the 1.83 meter difference between a astronaut's feet and head would be negligible and thus an astronaut would feel just as if he or she were on Earth. This is why space stations that intend to simulate gravity should be built large enough to minimize the significance of the difference between the radius of rotation of one's feet and one's head.
if you double the earths density say , standing at the surface you would experience twice the acceleration, weight would be doubled
When standing still.
This position greatly reduces stresses on a human body as the acceleration force is divided over greater area(back). If they were standing on their feet or sitting, stresses would be greater because of the lesser area, which could be potentially dangerous(risk of injury).
Yes. This is because the Moon has no significant amount of atmosphere.
The average rate of acceleration is (11/5) = 2.2 m/sec2 .
Its speed, velocity, and acceleration are all zero.
He's standing in the umbra of the lunar shadow.
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Standing at surface radius its = 9.82 (m/s)/sbut double the radius and the acceleration drops to 9.82 / ((2 / 1)2) = 2.455 (m/s)/s
If you're standing on something - yes. But if you're floating or falling, no.
If you are walking or standing still you are going slower than running, if you speed up then you are accelerating.