Yes. The following example demonstrates this:
#include<iostream>
struct foo {
foo(){ std::cout<<"foo"<<std::endl; }
~foo(){ std::cout<<"~foo"<<std::endl; }
};
int main()
{
int CNT=5;
foo * f = new foo[CNT];
delete [] f;
return(0);
}
Output:
foo
foo
foo
foo
foo
~foo
~foo
~foo
~foo
~foo
You cannot pass an array to a copy constructor. A copy constructor only accepts a constant reference to the object being copied, which must be of the same class as the object being constructed. An array is not an object of any class, and therefore cannot be used in any copy constructor. Although you cannot pass an array to a copy constructor, you can pass an array to a non-trivial constructor. It is not recommended, however, as there's no way to bounds-check the array being passed, which could result in an invalid object being created -- which is never a good thing. Even if you pass the array and its dimension(s) to the constructor, how can you guarantee those dimensions are valid for the array being passed? And what will you do if they are invalid? After all, you cannot veto the construction of an object once you've called its class constructor. Not knowing why you want to pass an array to a copy constructor, or how you intend to initialise the members via an array, makes it somewhat difficult to determine the best solution for you. However, I would consider using mutators instead of constructors. There's still the problem with bounds-checking but at least you won't have to deal with it during the object's construction.
'0' Try this: public static void main(String[] args){ } The output would be 0 even though you did not initialize any value in the int array.
An array literal is a comma-separated list of the elements of an array. An array literal can be used for initializing the elements of an array.
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
If by an object you mean a class or a struct, yes they can. Define the char array like you normally would but don't intialize any data into it. Do this in the constructor
An ordered array is simply an array where all elements are in sorted order: int a[] = {3, 6, 9, 10, 15, 21}; // ordered array An array can either be initialised with ordered elements or the elements may be sorted after initialisation. When inserting new elements into an ordered array, the order must be maintained.
The simplest way is to allocate raw memory of the required length using a pointer-to-pointer to the class of object. Once you have the memory, you can access the individual elements just as you would any other type of array, to either instantiate new objects or to point to existing objects.The following example uses the class itself to allocate a dynamic array of a given size, via a static member function.// Declare a simple class with a default constructor,// one member variable and a static member function.class MyClass{public:MyClass():m_int(0){} // Default constructor initialises member variable.private:int m_int; // Member variable.public:static MyClass** CreateArray(unsigned int count); // Static member function.};// Implementation of the static member function.MyClass** MyClass::CreateArray(unsigned int count){MyClass** ppResult = NULL;if( count ){// Calculate size of allocation.size_t size = count * sizeof( MyClass* );// Allocate memory and zero.if( ppResult = ( MyClass** ) malloc( size ))memset( ppResult, 0x00, size );}return( ppResult );}int main(){// Some variables.int i = 0;MyClass** ppArray;// Instantiate objects in a fixed-size array (uses default constructor).MyClass Array[10];// Instantiate a dynamic array of objects (and check for NULL).if( ppArray = MyClass::CreateArray( 10 )){// Point array elements to the existing objects.for( i=0; i
Elements of the array.
the length of the array
length
A single dimension array is an array with one dimension. It is a collection in memory of one or more elements of the same type. int array[100]; declares an array of int's of size 100 elements. The elements are referenced as array[0], the first one, through array[99], the last one.
0