yes
Any amount of gold is more dense than any amount of diamond. They don't even have to be the same amounts. Density is a characteristic of the substance. No matter whether you have a microscopic speck of it or a truckload of it, the density is the same.
The same way you determine the density of any other object. Divide the mass by the volume. Add: density = mass/volume = 5g/1mL = 5g/mL = 5g/cm3* *1mL = 1 cm3
5g of solid gold would take up less space than 5g of liquid gold because solids are typically more dense and pack their particles tightly together, while liquids have particles that can move and flow, resulting in a larger volume for the same mass.
To find the volume of 5 grams of gold, you can use the density of gold, which is approximately 19.32 grams per cubic centimeter (g/cm³). Volume is calculated using the formula: Volume = Mass / Density. Therefore, the volume of 5 grams of gold is about 0.259 cubic centimeters (cm³) when you divide 5 grams by the density of 19.32 g/cm³.
density=g/cm3 The density of Gold is 19.3g/cm3 The density of Fool's Gold (pyrite) is 5g/cm3 The question is slightly ambiguous as first written so two calculations are given: # 100/15= 6.666g/cm3 So this nugget is possibly pyrite and not gold. 100/5= 20g/cm3 So this nugget is possibly gold.
They are the same, but a 5G holds more songs and memory than a 3G.
5g is five grams and 0.5g is half a gram.
To calculate the volume, you can use the formula: Volume = Mass / Density. Given a mass of 35g and a density of 5g/cm³, the volume would be 35g / 5g/cm³ = 7 cm³. Therefore, the volume of the substance is 7 cm³.
5g/cm3
60g/12.0cm3=5g/cm3
20000 cm3
To find the number of moles of gold, first calculate the molar mass of gold, which is 197 g/mol. Then, divide the given mass of gold by the molar mass to find the number of moles. In this case, 3.60x10-5g ÷ 197 g/mol ≈ 1.83x10-7 moles of gold.