The octet rule only applies to elements that are heavy enough to have reached the second shell of electrons. In the first shell, the octet rule does not apply because the first shell is completed with only two electrons, not eight. So no, the octet rule does not apply to beryllium hydride.
Cl3CF
CF4 Doesn't violate the Octet Rule, the rest do.
Yes
The octet rule does not apply to transition metals.
There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.
Cl3CF
CF4 Doesn't violate the Octet Rule, the rest do.
Yes
The octet rule does not apply to transition metals.
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
F2ccf2
There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.
Sulfur is in period 3 and has 6 valence electrons. The expected fluoride would be SF2, SF^ a very stable compound is surprisoing. The bonding in SF6 has been described in a number of ways- one is that there is sp3d2 hybridisation and there are 6 equivalent 2 electron 2 center bonds. Other descriptions involve resonance of ionic canonicals where the octet is preserved. Yet another description is "hypervalency" involving 3 centre bonds. With BeH2 the situation is different, in this there are not enough electrons to form an octet. Some call this electron deficiency. In BeH2 each Be is surrounded by 4 hydrogen atoms, and there 4 BeHBe bonds- 3 center 2 electron. These are similar to bonds in B2H6. The octet rule is a guideline- it has proved to be remarkably useful- but as someone said ".. in inorganic chemistry the rule is that there are no rules"
In general, boron will form 3 covalent bonds, using each of its 3 valence shell electrons (sharing them). This will of course violate the octet rule, but obeys the sextet rule, and this is what makes boron stable. It (along with aluminum, eg.) do not obey the octet rule.
It does follow the octet rule!
Az important rule: any octet has to have eight parts, otherwise it is not an octet.
No, CH4 follows the octet rule.